查詢清單併發布多個結果表中的MySQL

Question

好傢伙即時通訊嘗試後幾個清單值到一個表在我的數據庫，但只需要一個單一的值到表...

Im做它像這樣的：

的形式爲：

<?php foreach($users as $user): ?> 
         <input type="checkbox" name="tipoinsertos" value="<?= $user['tipoinsertom']; ?>"> <?= $user['tipoinsertom']; ?> 
         <?php endforeach; ?> 

這是我的帖子格式：

$data = array('tipoinsertos' => $_POST['tipoinsertos']); 

try { 

    $dbh = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password); 

    $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 

    $query = "INSERT INTO barrasinternas (tipoinsertos) VALUES (:tipoinsertos)"; 


    $sth = $dbh->prepare($query); 
    $sth->execute($data); 
    echo "¡Añadida Exitosamente!"; 
    } 
catch(PDOException $e) 
    { 
    echo $sql . "<br>" . $e->getMessage(); 
    } 
$dbh = null; 
?> 

檢查此打印：

http://imgur.com/a/WRhFd

所以，我檢查了所有的3個值，但只有一個是我的表。

Answer 1

首先，使用數組爲你輸入名字tipoinsertos[]

<input type="checkbox" name="tipoinsertos[]" ... 

那麼你也沒告訴你是如何得到$data但你需要迭代和循環莫名其妙地執行該查詢。通過將它構建成一個大的查詢值，或者通過重複執行一個值來執行另一個語句。 Here's a possible solution：

<?php 

$users = [ 
    ['tipoinsertom' => 'Jonatan'], 
    ['tipoinsertom' => 'jeff'], 
    ['tipoinsertom' => 'joe'], 
]; 

?> 

<form method="POST"> 

<?php foreach($users as $user): ?> 
    <input type="checkbox" name="tipoinsertos[]" value="<?= $user['tipoinsertom']; ?>"> <?= $user['tipoinsertom']; ?> 
<?php endforeach; ?> 

    <input type="submit" value="Submit"/> 
</form> 

<?php 

// returns an intance of PDO 
// https://github.com/jpuck/qdbp 
$dbh = require __DIR__.'/tipoin_Dxa05i_A.pdo.php'; 


if(!empty($_POST['tipoinsertos'])){ 
    // prepare the query once 
    $query = "INSERT INTO barrasinternas (tipoinsertos) VALUES (:tipoinsertos)"; 
    $sth = $dbh->prepare($query); 

    // iterate through list 
    foreach($_POST['tipoinsertos'] as $tipoinsertos){ 
     $sth->execute(['tipoinsertos' => $tipoinsertos]); 
    } 

    // success 
    echo "&iexcl;A&ntilde;adida Exitosamente!"; 
    $dbh = null; 
}