如何從mysql返回多維數組並返回codeigniter

Question

如何使sql中的多維數組返回codeigniter中的行。從模型中返回值，保存$ res中的所有值？

$res = $this->user_model->get_room_book_join(['rooms.hotel_id' => 1]); 
    if ($res) { 
    echo '<pre>' 
    print_r($res) 
    } 

這是我的型號代碼。

function get_room_book_join($data) { 
    $this->db->join('room_overviews', 'rooms.room_id = 
    room_overviews.rom_id', 'left'); 
    $q = $this->db->get_where('rooms', $data); 
    return $q->result_array(); 
    } 

我得到這種類型的array.this類型不能幫助我。

Array(
    [0] => Array(
     [room_id] => 1 
     [room_no] => 101 
     [room_desc] => Double Bed Deluxe Non Air Conditioned 
     [status] => available 
     [category_id] => 1 
     [hotel_id] => 1 
     [tariff_type] => normal 
     [room_rate] => 1000 
     [persons] => 0 
     [date_start] => 0000-00-00 
     [date_end] => 0000-00-00 
     [overview_id] => 1 
     [rom_id] => 1 
     [hot_id] => 1 
     [cus_id] => 2 
     [bok_id] => 2 
     [dates] => 2017-04-12 
    ) 
    [1] => Array 
    (
     [room_id] => 1 
     [room_no] => 101 
     [room_desc] => Double Bed Deluxe Non Air Conditioned 
     [status] => available 
     [category_id] => 1 
     [hotel_id] => 1 
     [tariff_type] => normal 
     [room_rate] => 1000 
     [persons] => 0 
     [date_start] => 0000-00-00 
     [date_end] => 0000-00-00 
     [overview_id] => 2 
     [rom_id] => 1 
     [hot_id] => 1 
     [cus_id] => 2 
     [bok_id] => 2 
     [dates] => 2017-04-13 
    ) 
    [2] => Array 
    (
     [room_id] => 1 
     [room_no] => 101 
     [room_desc] => Double Bed Deluxe Non Air Conditioned 
     [status] => available 
     [category_id] => 1 
     [hotel_id] => 1 
     [tariff_type] => normal 
     [room_rate] => 1000 
     [persons] => 0 
     [date_start] => 0000-00-00 
     [date_end] => 0000-00-00 
     [overview_id] => 3 
     [rom_id] => 1 
     [hot_id] => 1 
     [cus_id] => 2 
     [bok_id] => 2 
     [dates] => 2017-04-14 
    ) 
    [3] => Array 
    (
     [room_id] => 1 
     [room_no] => 101 
     [room_desc] => Double Bed Deluxe Non Air Conditioned 
     [status] => available 
     [category_id] => 1 
     [hotel_id] => 1 
     [tariff_type] => normal 
     [room_rate] => 1000 
     [persons] => 0 
     [date_start] => 0000-00-00 
     [date_end] => 0000-00-00 
     [overview_id] => 4 
     [rom_id] => 1 
     [hot_id] => 1 
     [cus_id] => 2 
     [bok_id] => 2 
     [dates] => 2017-04-15 
    ) 
    [4] => Array 
    (
     [room_id] => 2 
     [room_no] => 102 
     [room_desc] => Double Bed Deluxe Non Air Conditioned Room 
     [status] => available 
     [category_id] => 1 
     [hotel_id] => 1 
     [tariff_type] => normal 
     [room_rate] => 1000 
     [persons] => 2 
     [date_start] => 0000-00-00 
     [date_end] => 0000-00-00 
     [overview_id] => 5 
     [rom_id] => 2 
     [hot_id] => 1 
     [cus_id] => 2 
     [bok_id] => 2 
     [dates] => 2017-04-12 
    ) 
    [5] => Array 
    (
     [room_id] => 2 
     [room_no] => 102 
     [room_desc] => Double Bed Deluxe Non Air Conditioned Room 
     [status] => available 
     [category_id] => 1 
     [hotel_id] => 1 
     [tariff_type] => normal 
     [room_rate] => 1000 
     [persons] => 2 
     [date_start] => 0000-00-00 
     [date_end] => 0000-00-00 
     [overview_id] => 6 
     [rom_id] => 2 
     [hot_id] => 1 
     [cus_id] => 2 
     [bok_id] => 2 
     [dates] => 2017-04-13 
    ) 
    [6] => Array 
    (
     [room_id] => 2 
     [room_no] => 102 
     [room_desc] => Double Bed Deluxe Non Air Conditioned Room 
     [status] => available 
     [category_id] => 1 
     [hotel_id] => 1 
     [tariff_type] => normal 
     [room_rate] => 1000 
     [persons] => 2 
     [date_start] => 0000-00-00 
     [date_end] => 0000-00-00 
     [overview_id] => 7 
     [rom_id] => 2 
     [hot_id] => 1 
     [cus_id] => 2 
     [bok_id] => 2 
     [dates] => 2017-04-14 
    ) 
    [7] => Array 
    (
     [room_id] => 2 
     [room_no] => 102 
     [room_desc] => Double Bed Deluxe Non Air Conditioned Room 
     [status] => available 
     [category_id] => 1 
     [hotel_id] => 1 
     [tariff_type] => normal 
     [room_rate] => 1000 
     [persons] => 2 
     [date_start] => 0000-00-00 
     [date_end] => 0000-00-00 
     [overview_id] => 8 
     [rom_id] => 2 
     [hot_id] => 1 
     [cus_id] => 2 
     [bok_id] => 2 
     [dates] => 2017-04-15 
    ) 
) 

其實我想要這種類型的數組。我怎麼能做到這一點。當['room_id']和['rom_id']都相等時，多維數組將被創建，['dates']將在單個數組[日期]中保存所有日期。

array(
[0]=>array(
    [room_id]=>1 
    [dates]=>array(
    [0]=>2014-04-12 
    [1]=>2014-04-13 
    [2]=>2014-04-14 
    [3]=>2014-04-15 
) 
) 
[1]=>array(
[room_id]=>2 
[dates]=>array(
    [0]=>2014-04-12 
    [1]=>2014-04-13 
    [2]=>2014-04-14 
    [3]=>2014-04-15 
))) 

Answer 1

查看此示例使用正常的PHP循環。效率不高，但它會做你的工作。

$dbResponse[] = array(
     'room_id' => 1, 
     'room_no' => 1, 
     'dates' => '2017-04-12', 
    ); 
$dbResponse[] = array(
     'room_id' => 1, 
     'room_no' => 1, 
     'dates' => '2017-04-13', 
    ); 
$dbResponse[] = array(
     'room_id' => 2, 
     'room_no' => 1, 
     'dates' => '2017-04-14', 
    ); 
$dbResponse[] = array(
     'room_id' => 2, 
     'room_no' => 1, 
     'dates' => '2017-04-15', 
    ); 

$updatedList = array(); 
foreach ($dbResponse as $key => $value) { 
    $updatedList[$value['room_id']][]=$value['dates']; 
} 

echo '<pre>'; 
print_r($updatedList); 
echo '</pre>'; 

$finalList = array(); 
foreach ($updatedList as $key => $value) { 
    $finalList[] = array(
      'room_id' => $key, 
      'dates' => $value 
     ); 
} 

echo '<pre>'; 
print_r($finalList); 
echo '</pre>'; 

Answer 2

更新回答

@ mi6crazyheart很好的答案。我想建議一點改變。您可以使用此代碼來完成任務。如果我用room_id替換索引鍵，我不認爲這很重要。

$dbResponse[] = array(
     'room_id' => 1, 
     'room_no' => 1, 
     'dates' => '2017-04-12', 
    ); 
$dbResponse[] = array(
     'room_id' => 1, 
     'room_no' => 1, 
     'dates' => '2017-04-13', 
    ); 
$dbResponse[] = array(
     'room_id' => 2, 
     'room_no' => 1, 
     'dates' => '2017-04-14', 
    ); 
$dbResponse[] = array(
     'room_id' => 2, 
     'room_no' => 1, 
     'dates' => '2017-04-15', 
    ); 

$updatedList = array(); 
foreach ($dbResponse as $key => $value) { 
    $updatedList[$value['room_id']]['room_id']=$value['room_id']; 
    $updatedList[$value['room_id']]['dates'][]=$value['dates']; 
} 

echo '<pre>'; 
print_r($updatedList); 
echo '</pre>'; 

老回答

您可以使用此代碼來解決你的問題。

我已經改變了結果數組的一點點，但我認爲這種格式的結果會更有幫助。（你可以從關鍵的房間ID）。

$result = array() 
foreach ($res as $row) { 
    if($row['room_id'] === $row['rom_id']) 
     $result[$res['room_id']]['dates'][] = $row['dates']; 
} 

如需更多幫助，我很樂意提供幫助。

快樂編碼！