需要幫助laravel 4.2

Question

我想在表格用戶中獲得用戶名，在帖子表中發帖ID並返回View::make('post.index')。我需要在post.index刀片中查看。

Database 
users table 

id 
username 

post table 
    id 
    message 
    posts_id 

Post.php @models folder 

    public function posts() 
    { 
     return $this->belongsTo('User'); 
    } 

User.php @models folder 


    public function post() 
    { 
     return $this->hasMany('Post'); 
    } 





PostController.php @controller folder 
    public function index() 
     { 

     $posts = Post::with('username')->get(); 
     return View::make('post.index')->with('posts', $posts); 
     } 




post/index.blade.php 

     the result here 
     i need to the result of author id become the username 

Answer 1

最佳做法： 模型類的名字應該是User和Post。數據庫表名應該是users和posts。

在Post.php文件，

public function user() 
{ 
    return $this->belongsTo('User'); 
} 

在 User.php文件

，

public function posts() 
{ 
    return $this->hasMany('Post'); 
} 

在事先你PostController.php

public function index() 
{ 
    $user_of_the_post = Post::find(postId)->user; //replace the postId //this will return the user object of the specified post 
    $user_name_of_the_author = $user_of_the_post->username; 
    **pass the necessary data to the view and print and return the view** 
}