如何從列中獲得最高5個值？

Question

我有產品表name和no_of_sell列.. 我想根據no_of_sell列從產品表中獲得最高5的銷售產品。 如何將它與查詢生成器一起使用？

$propular_products = DB::table('users') 
      ->join('products','products.auth_id','users.id') 
      ->select('products.*') 
      ->orderBy('products.no_of_sell', 'desc')    
      ->where('products.status','=','1') 
      ->paginate(5); 

假設products表：

name no_of_sell 
x  6 
y  9 
z  10 
t  23 
u  3 
h  11 
r  5 

我想找到

products list of 5 max no_of_sell ie, x y z t h 

Answer 1

所以，如果我理解正確列no_of_sell是int類型。我應該寫如下：

$best_sell = DB::table('products') 
      ->orderBy('no_of_sell', 'desc') 
      ->limit(5) 
      ->where('products.status','=','1') 
      ->paginate(4) 
      ->get(); 

https://laravel.com/docs/5.4/queries#retrieving-results https://laravel.com/docs/5.4/queries#ordering-grouping-limit-and-offset

Answer 2

$best_sell = DB::table('products') 
     ->select('no_of_sell') 
     ->where('products.status','=','1')      
     ->orderBy('no_of_sell', 'desc') 
     ->paginate(4); 

Answer 3

$best_sell = DB::table('products') 
     ->select() // your selection criteria 
     ->where('products.status','=','1') 
     ->take(5)->get();