我可以在Python中集成多個列表嗎？

Question

可能重複：
how can I iterate through two lists in parallel in Python?

我有3個表是這樣的：

name = ['sam', 'john', 'napoleon', 'tanaka', 'ming'] 
country = ['USA', 'England', 'France', 'Japan', 'China'] 
age = [23, 41, 19, 16, 55] 

，我想等的輸出：

sam; USA; 23 
john; England; 41 
napoleon; France; 19 
tanaka; Japan; 16 
ming; China; 55 

任何幫助將是偉大的。 由於事先

Answer 1

您可以使用zip()：

name = ['sam', 'john', 'napoleon', 'tanaka', 'ming'] 
country = ['USA', 'England', 'France', 'Japan', 'China'] 
age = [23, 41, 19, 16, 55] 
for x,y,z in zip(name,country,age): 
    print("{0}; {1}; {2}".format(x,y,z)) 

或使用map()：

mapp=map(lambda x,y,z:"; ".join((x,y,str(z))),name,country,age) 
for x in mapp: 
    print(x) 

輸出：

sam; USA; 23 
john; England; 41 
napoleon; France; 19 
tanaka; Japan; 16 
ming; China; 55 

Answer 2

假設列表長度相同：

for i in range(len(name)): 
    print '%s; %s; %s' %(name[i], country[i], age[i]) 

更新：這裏假定您使用的是Python 3.x.對於2.x，使用xrange來提高性能。或者：

for i in range(len(name)): 
    print '{0}; {1}; {2}'.format{name[i], country[i], age[i]} 

Answer 3

name = "sam john napoleon tanaka ming".split() 
country = "USA England France Japan China".split() 
age = [23, 41, 19, 16, 55] 

print "\n".join(["%s; %s %d" % (x) for x in zip(name,country,age)]) 

Answer 4

如果你知道他們都將具有相同的長度，那麼你可以做：

name = ['sam', 'john', 'napoleon', 'tanaka', 'ming'] 
country = ['USA', 'England', 'France', 'Japan', 'China'] 
age = [23, 41, 19, 16, 55] 

i = 0 

for n in name: 
    print name[i] + '; ' + country[i] + '; ' + str(age[i]) 
    i++ 

Answer 5

我的2美分;-)

從使用發電機itertools模塊：

from itertools import izip 

nlist = ['%s; %s; %s' %t for t in izip(name, country, age)]