1
我在angular2下面的代碼框架(TS):Angular2管理嵌套訂閱
a() {
return callService1.do(
z => {
callService2.subscribe(y => console.log("a callService2"))
console.log("callService1")
}
)
}
b() {
a.subscribe(
x => console.log("b subscribe callService1")
)
}
結果,我有:
"callService1"
"b subscribe callService1"
"a callService2"
我真的已經預計有"a callService2"
前"b subscribe callService1"
,我不確定明白這個結果。在b()中我的a.subscribe
之前完成callService2.subscribe
可以做些什麼?