2012-01-16 111 views
1

我有4個實體:Country,Region,Province,Town。使用DQL與Doctrine2實體和Zend框架混淆

<?php 

namespace Entities; 
use Doctrine\Common\Collections\ArrayCollection; 

/** 
* @Entity (repositoryClass="Repositories\Region") 
* @Table(name="regions") 
* @HasLifecycleCallbacks 
*/ 
class Region { 

    /** 
    * @Id @Column(type="integer") 
    * @GeneratedValue(strategy="AUTO") 
    */ 
    private $id; 

    /** @Column(type="string", length=30,unique=TRUE) */ 
    private $regionname; 

    /** @Column(type="boolean") */ 
    private $active; 

    /** 
    * @ManyToOne(targetEntity="Country", inversedBy="regions") 
    * @JoinColumn(name="countries_id", referencedColumnName="id",nullable=FALSE) 
    */ 
    private $countries_id; 

    /** 
    * @OneToMany(targetEntity="Province", mappedBy="provinces") 
    */ 
    private $provinces; 

    public function __construct() { 
     $this->provinces = new ArrayCollection(); 
     $this->active = true; 
    } 

<?php 

namespace Entities; 
use Doctrine\Common\Collections\ArrayCollection; 

/** 
* @Entity (repositoryClass="Repositories\Province") 
* @Table(name="provinces") 
* @HasLifecycleCallbacks 
*/ 
class Province { 

    /** 
    * @Id @Column(type="integer") 
    * @GeneratedValue(strategy="AUTO") 
    */ 
    private $id; 

    /** @Column(type="string", length=30,unique=TRUE) */ 
    private $provincename; 

    /** @Column(type="boolean") */ 
    private $active; 

    /** 
    * @ManyToOne(targetEntity="Region", inversedBy="provinces") 
    * @JoinColumn(name="regions_id", referencedColumnName="id",nullable=FALSE) 
    */ 
    private $regions_id; 

    /** 
    * @OneToMany(targetEntity="Town", mappedBy="towns") 
    */ 
    private $towns; 

    public function __construct() { 
     $this->towns = new ArrayCollection(); 
     $this->active = true; 
    } 

<?php 

namespace Entities; 
use Doctrine\Common\Collections\ArrayCollection; 

/** 
* @Entity (repositoryClass="Repositories\Town") 
* @Table(name="towns") 
* @HasLifecycleCallbacks 
*/ 
class Town { 

    /** 
    * @Id @Column(type="integer") 
    * @GeneratedValue(strategy="AUTO") 
    */ 
    private $id; 

    /** @Column(type="string", length=30,unique=FALSE) */ 
    private $townname; 

    /** @Column(type="boolean") */ 
    private $active; 
    // so that we know when a user has added a town 
    /** @Column(type="boolean") */ 
    private $verified; 

    /** 
    * @OneToMany(targetEntity="User", mappedBy="users") 
    */ 
    private $users; 

    /** 
    * @ManyToOne(targetEntity="Province", inversedBy="towns") 
    * @JoinColumn(name="provinces_id", referencedColumnName="id",nullable=FALSE) 
    */ 
    private $provinces_id; 

    public function __construct() { 
     $this->users = new ArrayCollection(); 

     $this->active = true; 
    } 

我想創建使用DQL的查詢,這將使我鎮的名單對於一個給定的區域。

爲了得到積極的城鎮的簡單列表我使用:

public function findActiveTowns($provinces_id = null) 
// we can pass in a specific provinces_id if we want 
{ 

    $qb = $this->_em->createQueryBuilder(); 
    $qb->select('a.townname, a.id') 
    ->from('Entities\Town', 'a'); 

    if (!is_null($provinces_id)){ 
     $qb->where('a.provinces_id = :provinces_id AND a.active = TRUE') 
     ->setParameter('provinces_id', $provinces_id); 
    } else { 
     $qb->where('a.active = TRUE'); 
    } 

    $towns=$qb->getQuery()->getResult(); 

    // make pairs array suitable for select lists 
    $options = array(); 
    foreach ($towns as $key => $value) { 
     $options[$value['id']] = $value['townname']; 
    } 
    return $options; 
} 

現在,言歸正傳。我如何設置連接並使其工作,以便我們可以傳入region_id並返回該地區的所有城鎮。

在本地SQL我會做這樣的事情:

SELECT towns.id 
FROM `towns` 
INNER JOIN `provinces` 
INNER JOIN `regions` 
WHERE regions.id =1 

感謝。

回答

3

首先有幾件事。

  1. 請勿將您的字段命名爲_id,因爲它們不是標識符,而是與其他對象的關係。加入列註釋與真實的DB名稱一起,對象模型中的字段不帶。
  2. 爲所有字段寫入/生成get/set/add方法來封裝它們,所以你可以使用它們。您無法從「外部」閱讀私人字段。

至於你的問題,還沒有測試過,但像這樣的東西應該工作。

class Town { 
    /** 
    * @ManyToOne(targetEntity="Province", inversedBy="towns") 
    * @JoinColumn(name="provinces_id", referencedColumnName="id",nullable=FALSE) 
    */ 
    private $province; 

class Province { 
    /** 
    * @ManyToOne(targetEntity="Region", inversedBy="provinces") 
    * @JoinColumn(name="regions_id", referencedColumnName="id",nullable=FALSE) 
    */ 
    private $region; 

$qb->select('a.townname, a.id') 
    ->from('Entities\Town', 'a') 
    ->leftJoin('a.province', 'p'); 

if (!is_null($provinces_id) && !is_null($region_id)){ 
    $qb->where('a.province = :province AND a.active = TRUE') 
     ->andWhere('p.region = :region') 
     ->setParameter('province', $provinces_id) 
     ->setParameter('region', $region_id); 
} else { 
    $qb->where('a.active = TRUE'); 
} 
+0

您好,感謝您的觀點。我確實有getter和setter,但是把它們排除在外以使代碼更短。 – dimbo 2012-01-16 17:49:41

+0

嗨,我一直試圖做LEFT加入整天,並不斷提出反對這個錯誤:「錯誤:類實體\鎮有沒有關聯名爲省」。我已經嘗試了上面的代碼(不包括WHERE條件),並且我得到了同樣的錯誤。有任何想法嗎? – dimbo 2012-01-16 17:52:32

+4

您應該重新命名私有$ provinces_id;私人$省;在你的城鎮實體,這應該做的伎倆! – 2012-01-16 20:25:27