2017-04-21 88 views
0
<div id="dialogButtons" class="opportunityEditorPopup">  
    <span id="closed" class="label checkOption" style="display: none;"><input type="checkbox">Mark this as closed</span> 
    <span class="testButtons" style="display: inline;"> 
      <button id="closeOpportunityButton" class="jqButton imaged ui-button ui-widget ui-state-default ui-corner-all ui-button-text-only" title="Close this opportunity" role="button"><span class="ui-button-text">Close</span></button> 
      <button id="newOrderButton" class="jqButton imaged ui-button ui-widget ui-state-default ui-corner-all ui-button-text-only" title="Raise New Quote" role="button"><span class="ui-button-text">New Quote</span></button> 
    </span> 
</div> 

所以我目前有以下的HTML,我想引用JQuery中的「closeOpportunityButton」。參考一個類中的按鈕ID

我有麻煩來然而,這並嘗試以下操作:

$('.testButtons #closeOpportunityButton').click(function(){ 
    console.log("test") 
}); 

$('#dialogButtons .testButtons #closeOpportunityButton').click(function(){ 
    console.log("test") 
}); 

無論其工作。

想法?

+1

ID都是唯一的,這樣只是'$( 「#closeOpportunityButton」)上( 「點擊」,函數(){的console.log( 「測試」)。 });'就夠了 – mplungjan

+1

你的代碼可以單獨運行:https://jsfiddle.net/a83ov97r/。檢查控制檯是否存在潛在的錯誤 –

+1

正如其他人所說的,ID是唯一的,你是否碰巧在你的文檔中有另一個ID = closeOpportunityButton? –

回答

0

嘗試在您的選擇中使用子選擇器。下面是代碼片段:

$('.testButtons > #closeOpportunityButton').click(function(){ 
 
    console.log("test") 
 
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> 
 
<span class="testButtons" style="display: inline;"> 
 
      <button id="closeOpportunityButton" class="jqButton imaged ui-button ui-widget ui-state-default ui-corner-all ui-button-text-only" title="Close this opportunity" role="button"><span class="ui-button-text">Close</span></button> 
 
      <button id="newOrderButton" class="jqButton imaged ui-button ui-widget ui-state-default ui-corner-all ui-button-text-only" title="Raise New Quote" role="button"><span class="ui-button-text">New Quote</span></button> 
 
    </span>