UIActivityView按鈕錯誤

我正在嘗試使用UIActivityView爲我的應用程序創建共享按鈕。當我按下應用程序中的按鈕時，出現錯誤。代碼有什麼問題？UIActivityView按鈕錯誤

@IBAction func shareButton(_ sender: UIButton) { 

     let texttoshare = "Sharing" 
     let URLtoshare = NSURL(string: "www.google.com") 
     let objectsToShare:NSArray = [texttoshare, URLtoshare!] 
     let activityVC = UIActivityViewController(activityItems: objectsToShare as! [Any], applicationActivities: nil) 

     self.present(activityVC, animated: true, completion: nil) 

      } 
    }

錯誤：是線程1：信號SIGABRT

來源

2016-11-04 Phillip

請將錯誤添加到您的問題。 –

嘗試更改'NSURL（字符串：...'到URL（字符串：...），並刪除'：NSArray' –

@LucianoRodríguez仍然是同樣的錯誤... – Phillip

試試這個。至少，它的工作對我來說沒有errores ..

let texttoshare = "Sharing" 
let URLtoshare = URL(string: "www.google.com") 
let activityVC = UIActivityViewController(activityItems: [texttoshare, URLtoshare!], applicationActivities: nil) 
self.present(activityVC, animated: true, completion: nil)

如果你想使用UIActivityViewController爲ipad公司，你需要爲activityVC指定popoverPresentationController?.sourceView。例如：

let texttoshare = "Sharing" 
let URLtoshare = URL(string: "www.google.com") 
let activityVC = UIActivityViewController(activityItems: [texttoshare, URLtoshare!], applicationActivities: nil) 
activityVC.popoverPresentationController?.sourceView = button... 
self.present(activityVC, animated: true, completion: nil)

來源

2016-11-04 10:35:37

你把什麼「按鈕... 「？我仍然得到相同的錯誤 – Phillip

任何你想要的...例如shareButton IBOutlet ...或者self.view，如果你願意的話，測試幾個視圖，看看有什麼適合你的需求...... –

UIActivityView按鈕錯誤

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