續集多對多自引用

Question

我試圖從關聯examples中獲得關聯工作正常的關聯之一，並且它似乎沒有正確設置連接表。在這個例子中，我們有一個叫Person的模型，然後是一個Person的孩子的多對多自我引用。代碼：

var Sequelize = require('sequelize'); 
var sequelize = new Sequelize('postgres://root@localhost/database_bug'); 

var Person = sequelize.define('Person', { 
    id: { 
    type: Sequelize.INTEGER, 
    primaryKey: true, 
    autoIncrement: true 
    }, 
    name: { 
    type: Sequelize.STRING, 
    allowNull: false 
    } 
}); 

Person.belongsToMany(Person, { as: 'Children', through: 'PersonChildren' }); 

Person.sequelize.sync({force:true}).then(function() { 
    Person.build({ name: 'John Doe' }).save().then(function(father) { 
    Person.build({ name: 'Jane Doe' }).save().then(function(daughter) { 
     father.addChild(daughter); 
    }); 
    }); 
}); 

但是，當我看着我的表在Postgres的我覺得自己像一個列上缺少自動生成的連接表。

  List of relations 
Schema |  Name  | Type | Owner 
--------+----------------+----------+------- 
public | People   | table | root 
public | People_id_seq | sequence | root 
public | PersonChildren | table | root 

            Table "public.People" 
    Column |   Type   |      Modifiers      
-----------+--------------------------+------------------------------------------------------- 
id  | integer     | not null default nextval('"People_id_seq"'::regclass) 
name  | character varying(255) | not null 
createdAt | timestamp with time zone | not null 
updatedAt | timestamp with time zone | not null 
Indexes: 
    "People_pkey" PRIMARY KEY, btree (id) 
Referenced by: 
    TABLE ""PersonChildren"" CONSTRAINT "PersonChildren_PersonId_fkey" FOREIGN KEY ("PersonId") REFERENCES "People"(id) 

      Table "public.PersonChildren" 
    Column |   Type   | Modifiers 
-----------+--------------------------+----------- 
createdAt | timestamp with time zone | not null 
updatedAt | timestamp with time zone | not null 
PersonId | integer     | not null 
Indexes: 
    "PersonChildren_pkey" PRIMARY KEY, btree ("PersonId") 
Foreign-key constraints: 
    "PersonChildren_PersonId_fkey" FOREIGN KEY ("PersonId") REFERENCES "People"(id) 

PersonChildren需要一個叫做沿着這些線路ChildId或某事的人鏈接到其子列。

People表：

database_bug=# SELECT * FROM "People"; 
id | name |   createdAt   |   updatedAt   
----+----------+----------------------------+---------------------------- 
    1 | John Doe | 2015-02-06 09:36:44.975-08 | 2015-02-06 09:36:44.975-08 
    2 | Jane Doe | 2015-02-06 09:36:44.985-08 | 2015-02-06 09:36:44.985-08 

怪異，我仍然選擇以確保daughter加入爲孩子father：

database_bug=# SELECT * from "PersonChildren"; 
     createdAt   |   updatedAt   | PersonId 
----------------------------+----------------------------+---------- 
2015-02-06 09:36:44.997-08 | 2015-02-06 09:36:44.997-08 |  2 

但PERSONID是2，而不是1 father應該添加daughter，而不是相反。

任何想法如何讓這個協會工作？

Answer 1

好的，看起來像文檔中的示例是錯誤的。公平地說，他們確實說過要使用hasMany，但後來用belongsToMany顯示了一個例子。

我改變belongsToMany到hasMany和它看起來我們是好去：

  Table "public.PersonChildren" 
    Column |   Type   | Modifiers 
-----------+--------------------------+----------- 
createdAt | timestamp with time zone | not null 
updatedAt | timestamp with time zone | not null 
PersonId | integer     | not null 
ChildId | integer     | not null 

database_bug=# select * from "PersonChildren"; 
     createdAt   |   updatedAt   | PersonId | ChildId 
----------------------------+----------------------------+----------+--------- 
2015-02-06 10:04:21.624-08 | 2015-02-06 10:04:21.624-08 |  1 |  2 

現在我能做的father.getChildren（），並承諾將返回兒童的名單。