8
你能告訴我如何傳遞一個JSON字符串,它看起來像這樣:如何解析JSON到目標C - SBJSON
{"lessons":[{"id":"38","fach":"D","stunde":"t1s1","user_id":"1965","timestamp":"0000-00-00 00:00:00"},{"id":"39","fach":"M","stunde":"t1s2","user_id":"1965","timestamp":"0000-00-00 00:00:00"}]}
我想它是這樣的:
SBJSON *parser =[[SBJSON alloc] init];
NSArray *list = [[parser objectWithString:JsonData error:nil] copy];
[parser release];
for (NSDictionary *stunden in list)
{
NSString *content = [[stunden objectForKey:@"lessons"] objectForKey:@"stunde"];
}
感謝推進你的JSON數據結構如下
問候
謝謝:)不知道在哪裏:) – Chris 2011-02-07 10:15:02