我不知道在replace value of
語句中是否可以使用xml。但你可以做到這一點。
declare @xml xml = '
<data>
<row>
<a>A</a>
<a>B</a>
<a>C</a>
</row>
</data>'
declare @Val1 varchar(10)
declare @Val2 varchar(10)
declare @Val3 varchar(10)
select
@Val1 = 'Data '+r.value('a[1]', 'varchar(1)'),
@Val2 = 'Data '+r.value('a[2]', 'varchar(1)'),
@Val3 = 'Data '+r.value('a[3]', 'varchar(1)')
from @xml.nodes('/data/row') n(r)
set @xml.modify('replace value of (/data/row/a/text())[1] with (sql:variable("@val1"))')
set @xml.modify('replace value of (/data/row/a/text())[2] with (sql:variable("@val2"))')
set @xml.modify('replace value of (/data/row/a/text())[3] with (sql:variable("@val3"))')
2版
declare @xml xml = '
<data>
<row>
<a>A</a>
<a>B</a>
<a>C</a>
</row>
<row>
<a>1</a>
<a>2</a>
<a>3</a>
</row>
</data>'
;with cte as
(
select
r.query('.') as Row,
row_number() over(order by (select 0)) as rn
from @xml.nodes('/data/row') n(r)
)
select
(select
'Data '+a.value('.', 'varchar(1)')
from cte as c2
cross apply Row.nodes('row/a') as r(a)
where c1.rn = c2.rn
for xml path('a'), root('row'), type)
from cte as c1
group by rn
for xml path(''), root('data')
感謝Mikael。我在其他網站上看到了這個解決方案,但它不是動態的。如果我有1000個「行」標籤,每個標籤都帶有1-100個「a」標籤? – Brian 2011-03-30 19:07:16
這是很棒的Mikael。謝謝。 – Brian 2011-04-01 12:03:20