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我無法讓我的腳本在不同的文件夾中工作。對Google App Engine來說很新,對於YAML來說是全新的。帶有多個文件夾的Google App Engine PHP
的文件夾結構是:
/login.php
/includes/mySQLConnection.php
的app.yaml
application: test
version: 1
runtime: php
api_version: 1
handlers:
- url: /includes
static_dir: includes
application_readable: true
- url: /login.php
script: login.php
的login.php
<?php
header('Content-type: application/json');
if($_POST) {
//Get Username and Password
$user_email = strip_tags(trim(strtolower($_POST['username'])));
$user_password = strip_tags(trim($_POST['password']));
//Connect to mySQL Server
include $_SERVER['DOCUMENT_ROOT']."includes/mySQL_connection.php";
// //Select which database to work with
$database = mysql_select_db("test",$mySQL_connection) or die("Cannot connect to user table");
echo json_encode(array('success' => 1,'error_message' => "Success"));
}
?>
/includes/mySQL_connection.php
<?php
$hostname = '127.0.0.1:3306';
$db_username = 'root';
$db_password = '';
//connection to the database
$mySQL_connection = mysql_connect($hostname, $db_username, $db_password) or die("Unable to connect to MySQL");
?>
這是行不通的,但是如果我將所有的代碼從/includes/mySQL_connection.php中取出並放到/login.php中,那麼它可以很好地工作。
任何人都可以指向正確的方向嗎?