即使這些值應該相等,它也不計算,並且它直接到else事件。表列名稱與數據庫匹配,所以...正確的方法來檢查局部變量是否等於局部變量
我需要某種類型的引號($ recruitcheck == $ recruitpass)嗎?
$recruiter = $_POST["recruiter"];
$recruitpass = $_POST["recruitpass"];
$recruitcheck = mysqli_query($maindb, "select aurapass from auras where auraname='$recruiter'");
if($recruitcheck == $recruitpass) {
$badgecheck = mysqli_query($maindb, "select recruitbadge from auras where auraname='$recruiter'");
if($badgecheck == "0") {
echo "<script>alert('Recruiter information correct, but there is no recruit badge.')</script>";
exit();
} else {
echo "<script>alert('Recruiter badge accepted.')</script>";
$emailcheck = mysqli_query($maindb, "select * from auras where email='$email'");
$namecheck = mysqli_query($maindb, "select * from auras where auraname='$auraname'");
if(mysqli_num_rows($emailcheck) > 0 || mysqli_num_rows($namecheck) > 0){
echo "<script>alert('New auraname/email is already taken.')</script>";
exit();
} else {
exit();
}
}
} else {
echo "<script>alert('Aura information of recruiter is incorrect. Please, use preexisting aura information to confirm recruiter identity.')</script>";
exit();
}
'$ recruitpass'是一個字符串,'$ recruitcheck'是__not__字符串。 –
通過用'var_dump'打印出來來檢查變量。 'mysqli_query'返回一個資源,所以它永遠不會等於一個字符串值。 http://php.net/manual/en/mysqli-result.fetch-row.php – dan08
獲取行以從數據庫獲取數據。 –