如何在改造中傳遞內容類型x-www-form-urlencoded的原始字符串？

Question

 OkHttpClient client = new OkHttpClient.Builder().addInterceptor(interceptor).addInterceptor(new Interceptor() { 
     @Override 
     public Response intercept(Chain chain) throws IOException { 
      Request.Builder requestBuilder = chain.request().newBuilder(); 
    requestBuilder.header("Content-Type", "application/x-www-form-urlencoded"); 
    requestBuilder.header("Accept", "text/json"); 
    requestBuilder.header("Authorization","Basic fh73hf78fhhf7at");  }).build(); 

Retrofit retrofit = new Retrofit.Builder().baseUrl(BASE_URL).client(client).addConverterFactory(GsonConv erterFactory.create()).build(); 
    BetaAPI betaAPI = retrofit.create(BetaAPI.class); 

所以在改裝 的接口（params爲類型， 「用戶名=大衛&密碼= test123 &範圍=的OpenID +電子郵件」 的）

@POST("core/connect/userinfo") 
    Call<ResponseBody> getLogin(@Body String params); 

Answer 1

你可以像這樣

@FormUrlEncoded 
@POST("core/connect/userinfo") 
Call<ResponseBody> getLogin(@Field("username") String username,@Field("password") String password, @Field("scope") String scope); 

或使用fieldMap註釋

@FormUrlEncoded 
@POST("core/connect/userinfo") 
Call<ResponseBody> getLogin(@FieldMap(encoded = true) Map<String, String> params);