試圖將目錄中的第n個文件複製到另一個文件夾

Question

我想生成一個隨機數，然後使用該隨機數來抓取目錄中的相應文件，這將隨後創建音樂歌曲的隨機播放列表。我採用3個參數，音樂路徑，新播放列表的名稱以及播放列表中要播放的歌曲數量。出於某種原因，在while循環它複製多個文件，而不是僅僅是第n個隨機文件的每一次迭代

#!/bin/bash 

#accepts 3 arguments path to music, name of the new playlist, and amount of songs you want in   the playlist 
path_to_music=$1; 
playlistname=$2; 
count=$3; 

#finds number of songs in directory, allows for more effective randomness 


#cd to the path where music is 
if [ -d "$path_to_music" ]; 
then 
    eval cd $path_to_music 
    numOfFiles=$(find . -type f | wc -l) 
else 
    echo "Directory does not exist, enter correct path." 
    read path_to_file 
fi 

ran=$[ ($RANDOM % 5) + 1 ] 
let ran=numOfFiles-ran; 
#make new folder where music is, will contain random songs (new playlist) 
mkdir $playlistname 

i=1 
while : #while loop finds a random song and copies it to folder created, $cnt is randomly generated so songs are random 
do 
    if [ "$i" -ne "$count" ]; 
    then  
     cnt=$[ ($RANDOM % 34) + 1 ] 
     let "cnt*=(-1)" 
     find -type f | head $cnt tail $cnt | xargs -I % cp % $path_to_music/$playlistname ; 
     let "i+=1" 
     echo $i 
    else 
     break; 
    fi 
done; 

Answer 1

什麼：

printf '%s\n' * | shuf | head -1 | xargs -I% cp % /another/dir/% 

Answer 2

命令head $cnt tail $cnt是畸形的;你的意思是head $cnt | tail -1。