嗨下面的LDAP查詢返回特定組中的成員「givenName」的列表。但是,我會返回特定組中成員的「sAMAccountName」列表。我對LDAP不太瞭解,並且不確定如何完成此操作。任何幫助表示讚賞。查詢活動目錄使用Java for samaccountname's綁定到特定組
public LdapContext getLdapContext(){
LdapContext ctx = null;
String connection = null;
try{
Hashtable<String, String> env = new Hashtable<String, String>();
env.put(Context.INITIAL_CONTEXT_FACTORY,
"com.sun.jndi.ldap.LdapCtxFactory");
env.put(Context.SECURITY_AUTHENTICATION, "Simple");
env.put(Context.SECURITY_PRINCIPAL, "userPrincipalName");
env.put(Context.SECURITY_CREDENTIALS, "Password");
env.put(Context.PROVIDER_URL, "domainController");
ctx = new InitialLdapContext(env, null);
connection = "Connection Successful.";
}catch(NamingException nex){
connection = "LDAP Connection: FAILED";
nex.printStackTrace();
}
this.getUserBasicAttributes("(&(objectClass=group)(CN=Users_Group))", ctx);
return ctx;
}
private void getUserBasicAttributes(String groupID, LdapContext ctx) {
try {
String userName = null;
String member = null;
SearchControls constraints = new SearchControls();
constraints.setSearchScope(SearchControls.SUBTREE_SCOPE);
String[] attrIDs = {"member"};
constraints.setReturningAttributes(attrIDs);
NamingEnumeration answer = ctx.search("DC=Domain,DC=com", groupID, constraints);
if (answer.hasMore()) {
Attributes attrs = ((SearchResult) answer.next()).getAttributes();
member = attrs.get("member").toString();
}else{
throw new Exception("Invalid Group");
}
} catch (Exception ex) {
ex.printStackTrace();
}
return;
}
上面的查詢結果類似於下:
member: CN=FistName
LastName,OU=ouData,OU=ouData,OU=ouData,DC=dcData,DC=dcData,DC=dcData,
CN=FistName2
LastName2,OU=ouData,OU=ouData,OU=ouData,DC=dcData,DC=dcData,DC=dcData,
CN=FistName3
LastName3,OU=ouData,OU=ouData,OU=ouData,DC=dcData,DC=dcData,DC=dcData,
CN=FistName4
LastName4,OU=ouData,OU=ouData,OU=ouData,DC=dcData,DC=dcData,DC=dcData
您好,這可能對您的研究有用:https://stackoverflow.com/questions/508014/active-directory-ldap-query-by-samaccountname-and-domain –