鏈接的URL @

Question

我在Thymleaf頁面下面的表格發送參數inThymleaf。 我以爲th:action="@{'/dashboard/makeAndSendInvoice(email=${po.Email})'}" 會做出這樣dashboard/makeAndSendInvoice/{Email}

一個鏈接所以我試圖得到它在這樣的方法：

@RequestMapping(method=POST, path="makeAndSendInvoice") 
    public String makeAndSendInvoice(@PathVariable("email") String email){ 

     System.out.println("Invoice is sent to..................."+email); 
     return "Invoice"; 
    } 

，但在我看來，這是行不通的，因爲它不承認我的方法。 因此，如何能接受我的方法

Answer 1

更改th:action到po.Email：

th:action="@{/dashboard/makeAndSendInvoice/{email}(email=${po.Email})}" 

，並在RequestMapping值添加PathVariable像：

@RequestMapping(method=POST, path="/dashboard/makeAndSendInvoice/{email:.+}") 
public String makeAndSendInvoice(@PathVariable("email") String email) { 

從Thymeleaf - Link URLs：

變量模板也允許URL路徑，像 @{/order/{orderId}/details(orderId=${orderId})}

<!-- Will produce '/gtvg/order/details?orderId=3' (plus rewriting) --> 
<a href="details.html" th:href="@{/order/details(orderId=${o.id})}">view</a> 

<!-- Will produce '/gtvg/order/3/details' (plus rewriting) --> 
<a href="details.html" th:href="@{/order/{orderId}/details(orderId=${o.id})}">view</a> 

從Spring - URI Template Patterns：

在Spring MVC，您可以使用一個方法 參數的@PathVariable註釋綁定它的價值URI模板變量：

@RequestMapping(value="/owners/{ownerId}", method=RequestMethod.GET) 
public String findOwner(@PathVariable String ownerId, Model model) { 
    Owner owner = ownerService.findOwner(ownerId); 
    model.addAttribute("owner", owner); 
    return "displayOwner"; 
}