合併多個oracle查詢以產生一個結果

[代碼]

select count(*) from tableA; 
select count(*) from tableB; 
select count(*) from tableC; 
select count(*) from tableD;

[/代碼]

即得到的結果是這樣的

|TablA|TableB|TableC|TableD| 
|50 |300 |30 |9|

感謝

來源

2011-05-05 ziggy

select * from 
(select count(*) from tableA), 
(select count(*) from tableB), 
(select count(*) from tableC), 
(select count(*) from tableD);

來源

2011-05-05 14:49:29 John

謝謝大家。這工作。 – ziggy 2011-05-05 14:55:03

下面應該與任何DBMS工作。

SELECT * 
FROM (select count(*) as tableA from tableA) a 
     full outer join (select count(*) as tableB from tableB) b 
     full outer join (select count(*) as tableC from tableC) c 
     full outer join (select count(*) as tableD from tableD) d

來源

2011-05-05 14:41:55

謝謝。這沒有用。它抱怨在字符'd'缺少關鍵字 – ziggy 2011-05-05 14:55:33

是

select count(*) from tableA; 
union all 
select count(*) from tableB; 
union all 
select count(*) from tableC; 
union all 
select count(*) from tableD;

來源

2011-05-05 14:43:44 xkonnectDeveloper

感謝這個工程，但它垂直顯示結果。 – ziggy 2011-05-05 14:56:04

謝謝，幫助很大！ – 2015-05-28 12:28:39

試試這個：

與
一個爲（SELECT COUNT（1）counterA，1從TableA的假人），兩成（選擇（1）作爲計數器B，1作爲表B中的虛擬計數器，三個爲（選擇計數（1）作爲計數器C，1作爲表C中的虛擬計數器），四個爲（選擇計數（1）作爲計數器D，1作爲dumm y from tableD）

select one.counterA，two.counterB，three.counterC，four.counterD from one，two，three，four where one.dummy = two.dummy and two.dummy = three.dummy and three。 dummy = four.dummy;

來源

2014-11-20 13:14:36 FerkiC

合併多個oracle查詢以產生一個結果

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