使用ast.literal_eval錯誤的Python請求語法無效？

Question

我是python的新手，並試圖使用ast.literal_eval來獲取請求數據，導致「無效語法」錯誤。

它打印數據我送這是格式一樣，

192.156.1.0,8181,database,admin,12345 

在Python中我展示它，但得到錯誤，而閱讀是我的代碼，上線數據

print str(request.body.read()) 
    datas = request.body.read() 
    data=ast.literal_eval(datas) 
    dbname = data['dbname'] 
    username = data['uname'] 
    ip = data['ip'] 
    port = data['port'] 
    pwd = data['pwd'] 

無效的語法錯誤= ast.literal_eval（數據）

如何解決它的建議將是可觀的

由於

Answer 1

變化這樣的：

192.156.1.0,8181,database,admin,12345 

這樣：

>>> a = "['192.156.1.0',8181,'database','admin',12345]" 
>>> ast.literal_eval(a) 
['192.156.1.0', 8181, 'database', 'admin', 12345] 

ast.literal_eval

ast.literal_eval(node_or_string) 

Safely evaluate an expression node or a Unicode or Latin-1 encoded string containing 
a Python literal or container display. The string or node provided may only consist of 
the following Python literal structures: strings, numbers, tuples, lists, dicts, booleans, and None. 

This can be used for safely evaluating strings containing Python values from untrusted 
sources without the need to parse the values oneself. It is not capable of evaluating 

任意複雜的表達式，例如涉及運營商或索引。

你可以嘗試這樣的：

>>> a='192.156.1.0,8181,database,admin,12345' 
>>> a = str(map(str,a.split(','))) 
>>> a 
"['192.156.1.0', '8181', 'database', 'admin', '12345']" 
>>> ast.literal_eval(a) 
['192.156.1.0', '8181', 'database', 'admin', '12345'] 

你的代碼看起來就像這樣：

data=ast.literal_eval(str(map(str,datas.split(',')))) 

Answer 2

什麼像

dbname, username, ip, port, pwd = request.body.read().split(',') 

測試

>>> str = "192.156.1.0,8181,database,admin,12345" 
>>> dbname , username , ip, port ,pwd = str.split(',') 
>>> dbname 
'192.156.1.0' 
>>> username 
'8181' 
>>> ip 
'database' 
>>> port 
'admin' 
>>> pwd 
'12345'