c＃對象到XML，休息服務

Question

我一直有400個錯誤的響應的問題，並已經把它歸結到正在通過的XML sting。該工程的字符串是

<Data xmlns=\"http://www.eysnap.com/mPlayer\"> 
<Name>Chris</Name> 
<Age>29</Age> 
<Period>123</Period> 
<msg>Why</msg> 
</Data> 

然而，當我嘗試seralize我得到它：

<?xml version="1.0" encoding="utf-16"?> 
<Data xmlns:Namespace="http://www.eysnap.com/mPlayer"> 
<Name>Chris</Name> 
<Age>29</Age> 
<Period>123</Period> 
<msg>Why</msg> 
</Data> 

我知道這是正確的格式，但我要麼需要XML輸出設置爲裸視或者我需要配置我的服務以接受正確的視圖。

客戶郵編：

 StringBuilder s = new StringBuilder(); 
     StringWriter writter = new StringWriter(s); 

     XmlWriterSettings settings = new XmlWriterSettings(); 
     settings.OmitXmlDeclaration=true; 

     using(XmlWriter writer = XmlWriter.Create(writter,settings)){ 
     XmlSerializer x = new XmlSerializer(d.GetType()); 
     XmlSerializerNamespaces ns = new XmlSerializerNamespaces(); 
     ns.Add("Namespace","http://www.eysnap.com/mPlayer"); 
     x.Serialize(writter,d,ns); 
     } 

     string invalid = s.ToString(); 
     string valid ="<Data xmlns=\"http://www.eysnap.com/mPlayer\"><Name>Chris</Name><Age>29</Age><Period>12 Years</Period><msg>Fucking hell</msg></Data>"; 
      req.ContentLength = valid.Length; 
      var sw = new StreamWriter(req.GetRequestStream()); 
      sw.Write(valid); 
      sw.Close(); 

      res = (HttpWebResponse) req.GetResponse(); 
      Stream responseStream = res.GetResponseStream(); 
      var streamReader = new StreamReader(responseStream); 

      //Read the response into an xml document 
      var soapResonseXmlDocument = new XmlDocument(); 
      soapResonseXmlDocument.LoadXml(streamReader.ReadToEnd()); 

      //return only the xml representing the response details (inner request) 
      TextBox1.Text = soapResonseXmlDocument.InnerXml; 
      //Response.Write(soapResonseXMLDocument.InnerXml); 

REST服務接口：

[OperationContract] 
    [WebInvoke(Method = "POST", 
     ResponseFormat = WebMessageFormat.Xml, 
     RequestFormat = WebMessageFormat.Xml, 
     BodyStyle = WebMessageBodyStyle.Wrapped, 
     UriTemplate = "auth")] 
    ResponseData Auth(Data rData); 

感謝

克里斯

Answer 1

如果你這樣做，而不是會發生什麼：

XmlSerializer x = new XmlSerializer(d.GetType(), "http://www.eysnap.com/mPlayer"); 
XmlSerializerNamespaces ns = new XmlSerializerNamespaces(); 
ns.Add(String.Empty, "http://www.eysnap.com/mPlayer");