SQL 5.1觸發語法錯誤

我有這樣的觸發器：SQL 5.1觸發語法錯誤

CREATE TRIGGER `VerficiaDispon` BEFORE INSERT ON `ordini` 
FOR EACH 
ROW 
BEGIN 
DECLARE temp INT 

SET temp = (SELECT disponibili FROM motoinstock 
      WHERE Moto = new.Moto_Comprata 
       AND Concessionario = new.Concessionario_Vendita); 

IF temp = 0 OR temp IS NULL THEN SIGNAL SQLSTATE '45000' 
    SET MESSAGE_TEXT = 'Moto non disponibile'; 

END IF ; 

SELECT acquisti 
INTO temp 
FROM clienticoncessionari 
WHERE cliente = new.Cod_Cliente 
AND concessionario = new.Concessionario_Vendita; 

IF temp %2 =1 THEN SET new.Prezzo_Vendita = (new.Prezzo_Vendita * 0.9) ; 

END IF ; 

END;

，我不能讓它在SQL 5.1工作。它給我一個錯誤的第7行。我嘗試選擇X到temp，設置temp =（...），但似乎沒有任何工作。我找不到sintax錯誤，有人可以幫我嗎？它必須是sql 5.1

來源

2012-07-06 Jack

我知道它應該是raise_application_error（8-2061，'derp'）;而不是SIGNAL SQLSTATE ... – Jack 2012-07-06 18:47:52

分隔符在哪裏？ – jcho360 2012-07-06 19:02:12

的分隔符應該是; – Jack 2012-07-06 19:07:18

Delimiter $$ 

CREATE TRIGGER `VerficiaDispon` BEFORE INSERT ON `ordini` 
FOR EACH 
ROW 
BEGIN 
DECLARE temp INT 

SET temp = (SELECT disponibili FROM motoinstock 
      WHERE Moto = new.Moto_Comprata 
       AND Concessionario = new.Concessionario_Vendita); 

IF temp = 0 OR temp IS NULL THEN SIGNAL SQLSTATE '45000' 
    SET MESSAGE_TEXT = 'Moto non disponibile'; 

END IF ; 

SELECT acquisti 
INTO temp 
FROM clienticoncessionari 
WHERE cliente = new.Cod_Cliente 
AND concessionario = new.Concessionario_Vendita; 

IF temp %2 =1 THEN SET new.Prezzo_Vendita = (new.Prezzo_Vendita * 0.9) ; 

END IF ; 

END 
$$ 

Delimiter ;

來源

2012-07-06 19:18:19 jcho360

我保持同樣的錯誤：＃1064 - 你的SQL語法錯誤;檢查與您的MySQL服務器版本相對應的手冊，以在'SET temp =（在第7行選擇disponibili FROM motoinstock WHERE Moto = new.M' – Jack 2012-07-07 07:46:15

SIGNAL語句只在MySQL 5.5中可用。

在5.1觸發使用信號將導致一個語法錯誤，因爲MySQL不知道這種說法。

來源

2012-07-06 21:18:43

好吧，我已經解決了幾乎所有問題。現在的代碼是這樣的：

delimiter $$ 
CREATE TRIGGER `VerficiaDispon` BEFORE INSERT ON `ordini` 
FOR EACH 
ROW 
BEGIN 

DECLARE temp integer; 
SET temp = (SELECT disponibili FROM motoinstock 
      WHERE Moto = new.Moto_Comprata 
       AND Concessionario = new.Concessionario_Vendita); 

IF temp=0 OR temp=NULL THEN 
RAISE_APPLICATION_ERROR(-20001,'NA'); 


SET temp = (SELECT acquisti FROM clienticoncessionari 
      WHERE cliente = new.Cod_Cliente 
       AND concessionario = new.Concessionario_Vendita); 

IF temp %2 =1 THEN SET new.Prezzo_Vendita = (new.Prezzo_Vendita * 0.9) ; 

END IF ; 


END 
delimiter ;

現在我的問題是關於IF。我不能提出一個錯誤，出於某種原因RAISE_APPLICATION_ERROR不會工作。其餘的都很好。有關如何處理錯誤的任何想法？

來源

2012-07-07 10:32:53 Jack

SQL 5.1觸發語法錯誤

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