休眠單向多對一查詢由孩子的財產

Question

@Entity 
public class Store {} 


@Entity 
@Table(name = "storeitem") 
public class StoreItem { 

    @Id @Column 
    private Integer storeId; 

    @Id 
    @ManyToOne @JoinColumn (name="productId", referencedColumnName="id") 
    private Product product; 

    @Column private Double cost; 
} 

mysql> desc storeitem; 
+-------------+---------------------+------+-----+---------+-------+ 
| Field  | Type    | Null | Key | Default | Extra | 
+-------------+---------------------+------+-----+---------+-------+ 
| StoreId  | int(10) unsigned | NO | PRI | 0  |  | 
| ProductId | bigint(20) unsigned | NO | PRI | 0  |  | 
| cost  | double unsigned  | NO |  | 0  |  | 



@Entity 
@Table(name = "product") 
public class Product { 
    @Id @GeneratedValue @Column(name = "Id") 
    private Long id; 

    @Column(name = "Name") 
    private String name; 
} 

mysql> desc product; 
+-------------+---------------------+------+-----+---------+----------------+ 
| Field  | Type    | Null | Key | Default | Extra   | 
+-------------+---------------------+------+-----+---------+----------------+ 
| Id   | bigint(20) unsigned | NO | PRI | NULL | auto_increment | 
| Name  | varchar(70)   | NO |  |   |    | 




Criteria cr=sess.createCriteria(StoreItem.class); 
cr.add(Restrictions.eq("product.name","butter")); 
cr.list(); 

當我試圖通過孩子的屬性過濾我得到這個下面例外

org.hibernate.QueryException: could not resolve property: product.name of:StoreItem 

Answer 1

HQL解決萬阿英，蔣達清

String hql="from StoreItem where productId in (select pd.id from Product pd where name = 'butter')"; 
Query query=sess.createQuery(hql); 
query.list(); 

Answer 2

Try{ 

    Criteria cr=sess.createCriteria(StoreItem.class, "si"); 
    crit.createCriteria("product","product").add(Restrictions.eq("name","butter")); 
    cr.list(); 

}