$query_message23 = "select * from messages_system as m, members as me where m.mes_id='$messageId' AND m.frm_id=me.mem_id";
它給輸出如何管理查詢?
Array ([mes_id] => 826 [mem_id] => 334 [frm_id] => 334 [subject] => Re: Re: Re: Re: Re: Hola! [body] => i dno i just made it up lollllllllllllllllllll
Artin wrote:
Haha.. Dooskie??? Is that Russian? lol
aurita wrote:
PFFFFFFT!!!!!!!!!!!
YOU KNOW HOW I DOOSKIE! LMAO!
你可以看到,mem_id和frm_id是相同的。怎麼樣?我很困惑。當我在phpmyadmin中運行這個查詢時,我從messages_system和members表中得到了mem_id 48和frm_id 334(因爲我加入了2個表)mem_id 334,所以我認爲這個成員的mem_id覆蓋了messages_system mem_id。
請建議。
感謝