我已經創建了一個實用程序的API來創建函數對象並調用其API函數的如何動態地將多個參數傳遞給函數?
function FunctionUtils() {
}
FunctionUtils.createFunctionInstance = function(functionName) {
var obj = FunctionUtils.createFunctionInstanceDescend(window, functionName);
return new obj();
}
FunctionUtils.createFunctionInstanceDescend = function(obj, path) {
var parts = path.split('.');
for(var i = 0; i < parts.length; i++) {
obj = obj[parts[i]];
}
return obj;
}
FunctionUtils.invokeAndInflate = function(object, functionName, parameterValue) {
object[functionName](parameterValue);
}
此的Util API的工作,爲下面的代碼:
function Student() {
var firstName;
var city, country;
this.getFirstName = function() {
return firstName;
}
this.setFirstName = function(val) {
firstName = val;
}
this.getAddress() {
return city + country;
}
this.setAddress(val1, val2) {
city = val1;
country = val2;
}
}
var student = FunctionUtils.createFunctionInstance("Student");
FunctionUtils.invokeAndinflate(student, "setFirstName", "Pranav"); //Works
FunctionUtils.invokeAndInflate(student, "setAddress", "LA", "USA"); //Doesn't Work.
如何使用FunctionUtils.invokeAndInflate API超過一個參數? ?
您可以從函數調用下降的參數,如果你想,從'arguments'讓他們所有。最後一個至少應該被刪除。 – 2013-05-13 13:45:01