我認爲我的JUnit測試會比我用單詞更好地解釋這個問題!Hibernate只執行查詢8次
@Test
public void query8times(){
for(int i=0; i<15; i++){
ProspectoRadarQueryBuilder prqb = new ProspectoRadarQueryBuilder("jardeu");
List<Object[]> prospectosNotas = (List<Object[]>) genericFilterDao.executeSQL(prqb.buildQuery());
System.out.println("------------------------------------- "+i);
}
}
對於在控制檯上的結果是:
Hibernate: SELECT * FROM ( select p.id, comparestrings('jardeu', pc.valor) as nota from com_prospecto p inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto) inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true) ) as subQuery where nota is not null AND nota > 0.35 order by nota desc;
------------------------------------- 0
Hibernate: SELECT * FROM ( select p.id, comparestrings('jardeu', pc.valor) as nota from com_prospecto p inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto) inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true) ) as subQuery where nota is not null AND nota > 0.35 order by nota desc;
------------------------------------- 1
Hibernate: SELECT * FROM ( select p.id, comparestrings('jardeu', pc.valor) as nota from com_prospecto p inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto) inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true) ) as subQuery where nota is not null AND nota > 0.35 order by nota desc;
------------------------------------- 2
Hibernate: SELECT * FROM ( select p.id, comparestrings('jardeu', pc.valor) as nota from com_prospecto p inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto) inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true) ) as subQuery where nota is not null AND nota > 0.35 order by nota desc;
------------------------------------- 3
Hibernate: SELECT * FROM ( select p.id, comparestrings('jardeu', pc.valor) as nota from com_prospecto p inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto) inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true) ) as subQuery where nota is not null AND nota > 0.35 order by nota desc;
------------------------------------- 4
Hibernate: SELECT * FROM ( select p.id, comparestrings('jardeu', pc.valor) as nota from com_prospecto p inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto) inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true) ) as subQuery where nota is not null AND nota > 0.35 order by nota desc;
------------------------------------- 5
Hibernate: SELECT * FROM ( select p.id, comparestrings('jardeu', pc.valor) as nota from com_prospecto p inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto) inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true) ) as subQuery where nota is not null AND nota > 0.35 order by nota desc;
------------------------------------- 6
Hibernate: SELECT * FROM ( select p.id, comparestrings('jardeu', pc.valor) as nota from com_prospecto p inner join com_prospecto_campo pc ON (p.id = pc.id_prospecto) inner join com_campo c ON (pc.id_campo = c.id AND c.flag_nome = true) ) as subQuery where nota is not null AND nota > 0.35 order by nota desc;
------------------------------------- 7
現在讓我們看看源代碼!
public List<?> executeSQL(String sql) {
EntityManager entityManager = entityManagerFactory.createEntityManager();
entityManager.getTransaction().begin();
Session hibernateSession = entityManager.unwrap(Session.class);
Query q = hibernateSession.createSQLQuery(sql);
return q.list();
}
我做了另一個試驗,與其他查詢
@Test
public void anotherQuery(){
for(int i=0; i<15; i++){
List<Object[]> prospectosNotas = (List<Object[]>) genericFilterDao.executeSQL("select * from com_campo");
System.out.println("------------------------------------- "+i);
}
}
下面是結果:
Hibernate: select * from com_campo
------------------------------------- 0
Hibernate: select * from com_campo
------------------------------------- 1
Hibernate: select * from com_campo
------------------------------------- 2
Hibernate: select * from com_campo
------------------------------------- 3
Hibernate: select * from com_campo
------------------------------------- 4
Hibernate: select * from com_campo
------------------------------------- 5
Hibernate: select * from com_campo
------------------------------------- 6
Hibernate: select * from com_campo
------------------------------------- 7
所以,I'm使用Spring數據...可能是什麼問題?
你是如何運行你的測試?我不能相信你原來的查詢被命名爲query8times是巧合。讓我相信你可能有一個測試類緩存在某個地方。 – Perception 2013-02-19 13:09:31
爲了確保,使它打印「Testing」+ n +「times」並在for循環中使用* n *。 – 2013-02-19 13:10:50
我懷疑你正在使用一個在更改'query8times'方法之前編譯的類文件。 – 2013-02-19 13:32:15