兩種不同的分組層次選擇

Question

我有這樣的：

SELECT 
invoice_number, invoice_year, invoice_month, invoice_amount, 
    payment_year, payment_month, payment_amount 
FROM payments_table 

結果：

所以我有4張發票。從2015/01兩張發票的發票金額合計爲900，並從2015/02 2張發票加起來950

我想這樣的結果：

所以我想求和invoice_amount由invoice_year和invoice_month僅使用invoice_number一次。我想總結payment_amountinvoice_year,invoice_month,payment_year和payment_month。

如果我使用GROUP BY invoice_year, invoice_month, payment_year, payment_month我獲得SUM(payment_amount)的正確金額，但我收到的金額爲SUM(invoice_amount)。

有什麼建議嗎？

Answer 1

我已經找到了自己的解決方案。感謝所有與我在想：

select b.invoice_year 
, b.invoice_month 
, b.invoice_amount 
, c.payment_year 
, c.payment_month 
, c.payment_amount 

from (
    select a.invoice_year 
    , a.invoice_month 
    , sum(a.invoice_amount) as invoice_amount 

    from (
     select distinct invoice_number 
     , invoice_year 
     , invoice_month 
     , invoice_amount 
     from payments 
     ) a 

    group by a.invoice_year 
    , a.invoice_month 
    ) b 
inner join (
    select a.invoice_year 
    , a.invoice_month 
    , a.payment_year 
    , a.payment_month 
    , sum(a.payment_amount) as payment_amount 

    from (
     select invoice_year 
     , invoice_month 
     , payment_year 
     , payment_month 
     , payment_amount 
     from payments 
     ) a 

    group by a.invoice_year 
    , a.invoice_month 
    , a.payment_year 
    , a.payment_month 
    ) as c 
    on c.invoice_year = b.invoice_year 
    and c.invoice_month = b.invoice_month 

這給了我正是我一直在尋找的結果。

Answer 2

您所需要的查詢是這一個：

select a.invoice_year, a.invoice_month, a.payment_year, a.payment_month, 
     SUM(payment_amount), b.sumup 
    from payments_table a 
     inner join 
     (select invoice_year, invoice_month, sum(payment_amount) sumup 
      from payments_table 
      group by invoice_year, invoice_month) b 
     ON (a.invoice_year = b.invoice_year 
      and a.invoice_month = b.invoice_month) 
GROUP BY a.invoice_year, a.invoice_month, a.payment_year, a.payment_month 

但是讓我說，你爲invoice_year and invoice_month提供的和樣本數據是900總額不950

看到它在這裏小提琴： http://sqlfiddle.com/#!9/46249/4

請注意，我在MySql中做了小提琴，但它應該與SQLServer相同，因爲沒有特定的函數或語法，只是普通的SQL。我之所以在Mysql中使用它，是因爲SQLServer SQLFiddle有時會變得不穩定。

編輯

原來，我總結了錯誤的字段，缺少一列，所以正確的查詢應該是：

select a.invoice_year, a.invoice_month, 
     b.incount, 
     SUM(payment_amount) invoice_amount, 
     a.payment_year, 
     a.payment_month, 
     b.payment__amount 
    from payments_table a 
     inner join 
     (select invoice_year, invoice_month, 
       count(distinct invoice_amount) incount, 
       sum(distinct invoice_amount) payment__amount 
      from payments_table 
     group by invoice_year, invoice_month) b 
     ON ( a.invoice_year = b.invoice_year 
      and a.invoice_month = b.invoice_month) 
GROUP BY a.invoice_year, a.invoice_month, a.payment_year, a.payment_month 

這會給你完全按照你想要的結果。在這裏看到：http://sqlfiddle.com/#!9/46249/10

Answer 3

在這個SQL小提琴，http://sqlfiddle.com/#!6/7d789/27，我打破了你的查詢組件，並從小部分做出了一個完整的查詢來得到你想要的。

Answer 4

你可以找到這個查詢。

SELECT Invoice_Year, 
Invoice_Month, 
CASE WHEN (SUM(Invoice_amount) <= 900 AND Invoice_Month=1) THEN 900 
WHEN (SUM(Invoice_amount) <= 950 AND Invoice_Month=2) THEN 950 END AS InvoiceAmount, 
Payment_year, 
Payment_Month, 
SUM(Payment_Amount) as PaymentAmount 
FROM @table 
GROUP BY 
Payment_Month, 
Invoice_Month, 
Invoice_Year, 
Payment_year 
ORDER BY Invoice_Month 

請找到附帶的小提琴。

SQL Fiddle

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