在Android中使用kso​​ap2調用.NET webservice，沒有結果返回

Question

我一直試圖通過android使用kso​​ap2（我已經嘗試過併成功獲得了不同的web服務）來調用簡單的.NET webservice（HelloWorld）。但是這個需要身份驗證，所以我搜索瞭如何爲身份驗證添加頭，但仍然沒有結果在我的textview中返回。

SoapObject Request = new SoapObject(NAMESPACE,METHOD_NAME); 
List<HeaderProperty> headers = new ArrayList<HeaderProperty>(); 
headers.add(new HeaderProperty("Authorization", "Basic"+Base64.encode("Username:Password".getBytes()))); 


     SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); 
     envelope.dotNet=true; 
     envelope.setOutputSoapObject(Request); 

     HttpTransportSE aht = new HttpTransportSE(URL); 


     try{ 
      aht.call(SOAP_ACTION,envelope,headers); 
      SoapPrimitive resultString = (SoapPrimitive)envelope.getResponse(); 

      tv.setText("yo :" + resultString); 

     } 
    catch(Exception e){ 
     e.printStackTrace(); 
    } 

我也曾經在我的日誌中記錄錯誤：

錯誤：螺紋連接的失敗，但我不認爲這是

這裏的來源是爲HelloWorld的WSDL方法：

>  <wsdl:types> 
>  <s:schema elementFormDefault="qualified" targetNamespace="http://tempuri.org/"> 
>  <s:element name="HelloWorld"> 
>  <s:complexType/> 
>  </s:element> 
>  <s:element name="HelloWorldResponse"> 
>  <s:complexType> 
>  <s:sequence> 
>  <s:element minOccurs="0" maxOccurs="1" name="HelloWorldResult" type="s:string"/> 
>  </s:sequence> 
>  </s:complexType> 
>  </s:element> 

我的問題。 有沒有人遇到過這種問題，或者我的代碼在某些時候是錯誤的？

Answer 1

試試這個：

SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); 
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
         SoapEnvelope.VER11);  
request.addProperty("requst_name",request_value);//if you have any request add here..     
envelope.setOutputSoapObject(request); 
envelope.implicitTypes = true; 
envelope1.dotNet = true; 
int Timeout = 60000; 
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL, Timeout); 
androidHttpTransport.debug = true; 
       try { 

        androidHttpTransport.call(SOAP_ACTION, envelope); 
        Object response = envelope.getResponse(); 
        String res=response.toString(); 
        } 

        }catch (XmlPullParserException e) { 

         e.printStackTrace(); 
        } catch (SocketTimeoutException e) { 
         // TODO Auto-generated catch block 
         e.printStackTrace(); 
        } catch (IOException e) { 
         // TODO Auto-generated catch block 
         e.printStackTrace(); 
        } 

Answer 2

。這是我如何訪問.NET Web服務。在我的情況我發送2個參數的用戶名和密碼，這裏的服務將根據database.If你不傳遞任何參數，請刪除我剛纔提到的參數和只添加這

PropertyInfo pi = new PropertyInfo(); 
    pi.setType(String.class); 
    request.addProperty(pi); 

---

字符串返回

else

public String Call(String username, String password) { 
    SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE, 
      OPERATION_NAME); 

    PropertyInfo pi = new PropertyInfo(); 
    pi.setName("username"); 
    pi.setValue(username); 
    pi.setType(String.class); 
    request.addProperty(pi); 

    pi = new PropertyInfo(); 
    pi.setName("password"); 
    pi.setValue(password); 
    pi.setType(String.class); 
    request.addProperty(pi); 

    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
      SoapEnvelope.VER11); 

    envelope.dotNet = true; 

    envelope.setOutputSoapObject(request); 

    HttpTransportSE httpTransport = new HttpTransportSE(SOAP_ADDRESS); 
    Object response = null; 

    try { 

     httpTransport.call(SOAP_ACTION, envelope); 
     response = envelope.getResponse(); 
    } 

    catch (Exception exception) { 
     response = exception.toString(); 
    } 

    return response.toString(); 
}