首先這是代碼。但這不是真正的代碼。如何使用Retrofit將數據設置爲listview?
API_Interface.java
public interface API_Interface{
@GET("/api/foo")
Call<Foo> foo_API();
}
foo.java
public class foo{
@SerializedName("foo")
@Expose
private String foo;
public String getFoo() {
return foo;
}
public void setFoo(String foo) {
this.foo = foo;
}
}
MainActivity.java
public class MainActivity extends AppCompatActivity{
String buzz;
Retrofit foo_retro;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
ListView listView = (ListView) findViewById(R.id.list_view);
ArrayList<foo> fooList = new ArrayList<foo>();
FooAdapter fooAdapter = new FooAdapter(this, 0, fooList);
listView.setAdapter(fooAdapter);
...
foo_retro = new Retrofit.Builder()
.baseUrl("http://api.foo.com")
.addConverterFactory(GsonConverterFactory.create())
.build();
API_Interface foo_service = foo_retro.create(API_Interface.class)
Call<foo> foo_call=foo_service.foo_API();
foo_call.enqueue(new Callback<foo>() {
@Override
public void onResponse(Call<foo> call, Response<foo> response) {
buzz = response.body().getFoo();
System.out.println(buzz);
}
@Override
public void onFailure(Call<zaifExchange> call, Throwable t) {
Toast.makeText(MainActivity.this, "Error", Toast.LENGTH_SHORT);
}
});
fooList.add(new foo(buzz));
System.out.println(buzz);
}
}
當我運行這段代碼,我可以和打印buzz
(如「蘋果「)在onResponse
方法中。 但是,我無法將數據設置爲listview
(buzz
爲空)。 我知道原因是enqueue
是異步的,所以終端顯示:
I/System.out: null
I/System.out: Apple
那麼,應該怎麼辦? 謝謝。
你的API響應是什麼? – Kuls
onResponse將響應數據設置爲您的數組列表「fooList」,並設置爲適配器 –