獲取今天和昨天的時間戳在php

Question

如何通過在php中使用strtotime（）函數獲取今天，昨天和前天的12點的時間戳？

12點鐘是一個變量，會被用戶更改。

Answer 1

$hour = 12; 

$today    = strtotime($hour . ':00:00'); 
$yesterday   = strtotime('-1 day', $today); 
$dayBeforeYesterday = strtotime('-1 day', $yesterday); 

Answer 2

的strtotime支持許多interesting modifiers可以使用：

$hour = 12; 

$today    = strtotime("today $hour:00"); 
$yesterday   = strtotime("yesterday $hour:00"); 
$dayBeforeYesterday = strtotime("yesterday -1 day $hour:00"); 

echo date("Y-m-d H:i:s\n", $today); 
echo date("Y-m-d H:i:s\n", $yesterday); 
echo date("Y-m-d H:i:s\n", $dayBeforeYesterday); 

它可以作爲預測：

2011-01-24 12:00:00 
2011-01-23 12:00:00 
2011-01-22 12:00:00 

Answer 3

OO等效

$oToday = new DateTime(); 
$oToday->setTime($iHour, 0); 

$oYesterday = clone $oToday; 
$oYesterday->modify('-1 day'); 

$oDayBefore = clone $oYesterday; 
$oDayBefore->modify('-1 day'); 

Answer 4

得到的開始昨天

$oDate = new DateTime(); 
$oDate->modify('-1 day'); 
echo $oDate->format('Y-m-d 00:00:00'); 

結果

2014-11-05 00:00:00 

Answer 5

由於PHP 7，你可以寫類似this：

$today = new \DateTime(); 
$yesterday = (clone $today)->modify('-1 day'); 
$dayBefore = (clone $yesterday)->modify('-1 day'); 
// Then call ->format('Y-m-d 00:00:00'); on each objects 

Answer 6

您可以輕鬆地找到使用DateTime對象的任何日期，它是如此的靈活

$yesterday = new DateTime('yesterday'); 
echo $yesterday->format('Y-m-d'); 

$firstModayOfApril = new DateTime('first monday of april'); 
echo $firstModayOfApril->format('Y-m-d'); 

$nextMonday = new DateTime('next monday'); 
echo $nextMonday->format('Y-m-d'); 

Answer 7

您還可以使用new DateTime("now")爲今天new DateTime("1 day ago")爲昨天或所有可以解析由strtotime PHP功能。

然後根據需要格式化。