類型錯誤：無法轉換「詮釋」對象STR基因座的數學方程式隱含變量

Question

我是新來的蟒蛇，但我試圖把DogAge成數學方程式，仍然沒有工作

Animal = input("dog or cat? ") 

if Animal == "dog": 
    DogAge = int(input("how old is you dog? ")) 
else: 
    CatAge = int(input("how old is your cat? ")) 

if DogAge == 1: 
    print("your dog's age is 11") 
elif DogAge == 2: 
    print("your dog's age is 22") 
else: 
    print("your dog's age is " + (DogAge - 2 * 4 + 22)) 

給出：

 
TypeError: Can't convert 'int' object to str implicitly 

Answer 1

錯誤指出發生了什麼問題。更改此：

print("your dog's age is " + (DogAge - 2 * 4 + 22)) 

要這樣：

print("your dog's age is " + str(DogAge - 2 * 4 + 22)) 

不能連接字符串對象與一個整數。

Answer 2

另一種解決方案：

print("your dog's age is {0}".format((DogAge - 2) * 4 + 22)) 

（假設你要計算(DogAge-2) * 4 + 22，不DogAge + 14）。

Answer 3

您可能需要考慮以不同的方式重新組織代碼，以分開計算狗的年齡和實際打印的值。

因爲稍後有可能將該代碼重構爲函數，如果它變得更復雜。

Animal = input("dog or cat? ") 

if Animal == "dog": 
    DogAge = int(input("how old is you dog? ")) 
else: 
    CatAge = int(input("how old is your cat? ")) 

if DogAge == 1: 
    calculated_dogs_age = 11 
elif DogAge == 2: 
    calculated_dogs_age = 22 
else: 
    calculated_dogs_age = DogAge - 2 * 4 + 22 

print("your dog's age is {0:d}".format(calculated_dogs_age))