創建觸發器Mysql

Question

將表Aluguel更新字段中的狀態插入到忙後。

不工作。

DELIMITER $$ 
CREATE TRIGGER Tgr_Status_Update AFTER INSERT 
ON aluguel 
FOR EACH ROW 
    BEGIN 
     UPDATE apartamento SET status_apart = busy 
     WHERE id_apart = apartamento_id_apart; 
    END$$ 
DELIMITER ; 

Answer 1

，你必須使用新的關鍵字

DELIMITER $$ CREATE TRIGGER Tgr_Status_Update AFTER UPDATE 

ON aluguel FOR EACH ROW 

BEGIN UPDATE apartamento SET status_apart = new.busy 

WHERE id_apart = new.apartamento_id_apart; 

END$$ DELIMITER ; 

----------------------------- ----------插入觸發器-----------------

DELIMITER $$ CREATE TRIGGER Tgr_Status_Insert AFTER INSERT 

ON aluguel FOR EACH ROW 

BEGIN UPDATE apartamento SET status_apart = new.busy 

WHERE id_apart = new.apartamento_id_apart; 

END$$ DELIMITER ; 

Answer 2

要引用要插入到表中的列，你需要使用NEW.column_name。

如果busy是一個字符串，則需要將其放在引號中。

DELIMITER $$ 
CREATE TRIGGER Tgr_Status_Update AFTER INSERT 
ON aluguel 
FOR EACH ROW 
    BEGIN 
     UPDATE apartamento SET status_apart = 'busy' 
     WHERE id_apart = NEW.apartamento_id_apart; 
    END$$ 
DELIMITER ; 

DEMO