HTML與PHP的檢查清單

Question

我在PHP中有以下形式的操作。我已使用檢查清單來獲取項目名稱。如果我選擇列表中的項目，它將以Array，Array而不是原始值（即Tatvam，Amairo，Vedam）出現。

我收到的消息是這樣

jQuery(".form-js-contact").submit(function() { 
    var thisform = jQuery(this); 
    jQuery('.required-error',thisform).remove(); 
    var aname = jQuery("#aname").val(); 
    var amail = jQuery("#amail").val(); 
    var aphone = jQuery("#aphone").val(); 
    var acomments = jQuery("#acomments").val(); 
    var color = jQuery("input[name='color[]']").serializeArray(); 

    var psubject = jQuery("#psubject").val(); 

    var data = {'aname':aname,'amail':amail,'aphone':aphone,'acomments':acomments,'psubject':psubject,'color':color}; 
    if (aname == "") { 
     jQuery("#aname").after('<span class="form-description required-error">Required field.</span>'); 
    }else { 
     jQuery("#aname").parent().find('.required-error').remove(); 
    } 
    if (amail == "") { 
     jQuery("#amail").after('<span class="form-description required-error">Required field.</span>'); 
    }else { 
     jQuery("#amail").parent().find('.required-error').remove(); 
    } 
    if (aphone == "") { 
     jQuery("#aphone").after('<span class="form-description required-error">Required field.</span>'); 
    }else { 
     jQuery("#aphone").parent().find('.required-error').remove(); 
    } 
    if (acomments == "") { 
     jQuery("#acomments").after('<span class="form-description required-error">Required field.</span>'); 
    }else { 
     jQuery("#acomments").parent().find('.required-error').remove(); 
    } 



    if (aname != "" && amail != "" && aphone != "" && acomments != "") { 
     jQuery.post("contact_us_contact.php",data,function (result) { 
      if (result == "done") { 
       thisform.prepend("<div class='alert-message success-contact'><p><strong>Thank you "+name+"!</strong> We'll be in touch real soon .</p></div>"); 
       jQuery("#aname").val(""); 
       jQuery("#amail").val(""); 
       jQuery("#aphone").val(""); 
       jQuery("#acomments").val(""); 

      } 
     }); 
    } 
    return false; 
}); 

這是我的HTML代碼

<form class="form-style form-js-contact" action="contact_us_contact.php" method="post"> 
         <input type="hidden" name="psubject" id="psubject" value="Enquiry from Contact Page"> 
<div class="col-md-6 col-lg-6" > 
<input class=required-item value="" name=aname id=aname aria-required=true placeholder="Your Name*"></div> 
<div class="col-md-6 col-lg-6" ><input type=email class=required-item id=amail name=amail value="" aria-required=true placeholder="Your Email*"></div> 
<div class="col-md-6 col-lg-12" ><input class=required-item aria-required=true id=aphone name=aphone value="" placeholder="Your Phone*"></div> 

<div class="col-md-3" style="margin-bottom:10px; "><h4>Projects Interested</h4></div> 
<div class="col-md-2" ><input name="color[]" id="color" class="check" type="checkbox" value="Amairo">Amairo</div> 
<div class="col-md-2" ><input name="color[]" id="color" class="check" type="checkbox" value="Tatvam">Tatvam</div> 
<div class="col-md-2" ><input name="color[]" id="color" class="check" type="checkbox" value="Vedam">Vedam</div> 

<div class="col-md-6 col-lg-12" > 
<textarea name="acomments" id="acomments" class=required-item aria-required=true placeholder="Type Your Message*"></textarea></div> 
<div class="col-md-6 col-lg-6" > 
<input style=font-size:16px name=submit type=submit value="Send Enquiry" class="submit_buttom buttonColor" id="Main_Contact_Form"></div> 
</form> 

這是我的PHP

 <?php 
    function clean_text($text='') { 
    $text = trim($text); 
    $text = strip_tags($text); 
    $text = addslashes($text); 
    $text = htmlspecialchars($text); 
    return $text; 
    } 
    if (!$_POST) { 
    die(); 
    }else { 
    if (empty($_POST["aname"]) && empty($_POST["aphone"]) &&  empty($_POST["amail"])&& empty($_POST["acomments"])) { 
    echo "all_empty"; 
}else if (empty($_POST["aname"])) { 
    echo "empty_name"; 
}else if (empty($_POST["amail"])) { 
    echo "empty_mail"; 
}else if (empty($_POST["aphone"])) { 
    echo "empty_phone"; 
}else if (empty($_POST["acomments"])) { 
    echo "empty_Comments"; 
}else {  
    $your_email = "mail@mydomain.com";  
    $aname = clean_text($_POST["aname"]); 
    $amail = clean_text($_POST["amail"]); 
    $aphone = clean_text($_POST["aphone"]); 
    $acomments = clean_text($_POST["acomments"]); 
    $wname = $_POST['color']; 
    $psubject = clean_text($_POST["psubject"]); 
    $subject = "$psubject"; 

    $headers = "From: leads@mydomain.in". "\r\n"; 
    $headers .= 'Content-type: text/html; charset=UTF-8'. "\r\n"; 
    $msg  = "New Message \n\r <br>"; 
    $msg  .= "Name : \t $aname \r\n <br>"; 
    $msg  .= "Email : \t $amail \r\n<br>";  
    $msg .= "Phone : \t $aphone \r\n<br>"; 
    $msg .= "Message : \t $acomments \r\n<br>"; 
    if (isset($wname)) { 
    $msg .= "Project(s) Interested: \r\n"; 
    $msg .= "<ul> \r\n"; 
    foreach ($wname as $color){ 
    $msg .="<li>" .$color. "</li> \r\n"; 
} 

    $msg .= "</ul>"; 

    } // isset 

    echo "done"; 
    $done = @mail($your_email, $subject, $msg, $headers); 
    } 
} 

？>

Answer 1

您正在使用的ID jQuery("#color").val();和取色值的jQuery根據HTML規則，只有一個具有相同名稱的標識，因此您只能獲得一個值。你必須更換喜歡

> jQuery 

var color = jQuery("input[name='color[]']").serializeArray(); 

，然後你會得到PHP代碼顏色的所有值$wname = $_POST['color'];

Answer 2

在你的PHP代碼

$wname  = implode(",", $_POST['color']); 

替換此

$wname  = $_POST['color']; 

因爲你是從HTML傳遞name="color[]"作爲數組。

Answer 3

您的代碼出現了錯誤

下似乎是錯誤的

if (isset($_POST['wname'])) {...} 

我相信它應該是

if (isset($wname)) {...}