我（1054，「字段列表」中的未知列'rango_category.slug'）Django

Question

我試圖在Django項目中創建一個slug字段。 但是，當我嘗試訪問django admin上的類別時，我一直在收到這個錯誤，我剛接觸Django並試圖跟上教程。

+----------------+----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+ 
| Table   | Create Table                                                                 | 
+----------------+----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+ 
| rango_category | CREATE TABLE `rango_category` (
    `id` int(11) NOT NULL AUTO_INCREMENT, 
    `name` varchar(128) NOT NULL, 
    `likes` int(11) NOT NULL, 
    `views` int(11) NOT NULL, 
    PRIMARY KEY (`id`), 
    UNIQUE KEY `name` (`name`) 
) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=latin1 | 
+----------------+----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+ 

Models.py文件

from django.db import models 
from django.template.defaultfilters import slugify 

# Create your models here. 
class Category(models.Model): 
    name = models.CharField(max_length=128, unique=True) 
    views = models.IntegerField(default=0) 
    likes = models.IntegerField(default=0) 
    slug = models.SlugField(unique=True) 

    class Meta: 
      verbose_name_plural = "Categories" 


    def save(self, *args, **kwargs): 
      self.slug = slugify(self.name) 
      super(Category, self).save(*args, **kwargs) 

    def __unicode__(self): 
      return self.name 

class Page(models.Model): 
    category = models.ForeignKey(Category) 
    title = models.CharField(max_length=128) 
    url = models.URLField() 
    views = models.IntegerField(default=0) 

    def __unicode__(self): 
      return self.title 

Answer 1

正如你所看到的，你不必在你rango_category表slug場。

在爲rango_category表相應的模型，假設RangoCategory模型添加蛞蝓場：

class RangoCategory(models.Model): 
    id = ... 
    likes = ... 
    name = ... 
    views = ... 
    slug = models.SlugField() 

然後運行python manage.py makemigrations和python manage.py migrate，它可能會要求值設置爲現有行。

這將在您的db表中創建一個slug字段。