如何從提取數組結果中檢索單選按鈕的選定值..？

Question

我想獲取單選按鈕在提取的記錄中的選定值的值..我沒有得到單選按鈕值...告訴我，如果它是正確的或錯誤的..在這種情況下，它是動態的..如果它是靜態的沒有問題..但這是動態的..怎麼做.. ..？或任何替代方法..任何幫助將是可觀的..

<?php 
while($res = mysql_fetch_array($result)) { 

echo "<tr>"; 
echo "<td>". "<input type='radio' name= 'Returns' 
value=".$res['T_no'].")>". "</td>"; 
echo "<td>".$res['T_no']."</td>"; 
?> 

<form action="sample.php" method="POST" class="form-inline"> 
<input type="submit" value="Get Sch"/> 
</form> 

sample.php 

<?php 
$con = mysql_connect("localhost", "root", ""); 
if ($con) { 
$db = mysql_select_db('tdb', $con); 
} else { 
die('Could not connect: ' . mysql_error()); 
} 

echo "you have selected :".$_POST['Returns']; // Displaying Selected Value 

echo $POST['Returns']; 

$selected_val = $_POST['Returns']; // Storing Selected Value In Variable 
echo "You have selected :" .$selected_val; // Displaying Selected Value 

$result = mysql_query("SELECT * FROM t_detail WHERE 
T_No='$selected_val'"); 

mysql_close($con) 
?> 

Answer 1

在你的代碼已經使用$_POST['Returns[]']應該$_POST['Returns']。因爲這是一個數組，所以你既可以implode或使用foreach讓每個單選按鈕值

您可以如下操作：

<form action="schedule.php" method="POST" class="form-inline"> 
<?php 
while($res = mysql_fetch_array($result)) { 

echo "<tr>"; 
echo "<td>". "<input type='radio' name= 'Returns' 
value=".$res['Train_no'].")>". "</td>"; 
echo "<td>".$res['Train_no']."</td>"; 
?> 
<input type="submit" value="Get Schedule"/> 
</form> 

============= =

$implode = implode(',',$selected_val); 
$result = mysql_query("SELECT * FROM train_detail WHERE 
Train_No='".$implode."'");