與array_count_values獲取兩個相同的值

我有一個數組，我想獲得所有不同的值。與array_count_values獲取兩個相同的值

，我有優秀作品的代碼，直到一個點......

$array_for_19_2=[ 
["A 1","A 1","A 1","A 2","A 3","A 2","A 1","A 3","A 2","A 1","A 3","A 3","A 2","A 1","A 2"], 
["A a","A a","A c","A a","A c","A c","A c","A a","A a","A c","A c","A a","A a","A a","A c"], 
["A X","A Y","A Z","A Z","A Z","A Y","A X","A X","A X","A X","A Z","A Z","A X","A Z","A Y"], 
["1 a","1 b","1 a","1 a","1 b","1 c","1 b","1 c","1 b","1 a","1 a","1 c","1 b","1 a","1 a"], 
["2 a","2 a","2 a","2 a","2 a","2 a","2 a","2 b","2 b","2 a","2 a","2 b","2 a","2 b","2 b"], 
["3 b","3 c","3 b","3 c","3 a","3 b","3 c","3 b","3 b","3 b","3 c","3 c","3 a","3 c","3 b"], 
["a X","a X","a Z","a Y","a Z","a X","a Y","a Z","a Z","a Z","a X","a X","a Y","a Y","a Z"], 
["b Z","b Z","b X","b Z","b Z","b Z","b Z","b X","b Y","b Y","b X","b X","b Y","b Y","b Z"], 
["c Y","c Y","c Y","c Y","c Z","c Z","c X","c X","c Z","c Y","c Y","c X","c Z","c Y","c X"], 
["1 Z","1 Z","1 X","1 Y","1 X","1 Z","1 X","1 Y","1 Y","1 Z","1 X","1 Z","1 Y","1 Y","1 Y"], 
["2 X","2 X","2 Y","2 Z","2 Y","2 X","2 X","2 Z","2 Y","2 Y","2 Y","2 X","2 Y","2 X","2 X"], 
["3 X","3 X","3 Y","3 X","3 Y","3 Y","3 Y","3 X","3 Z","3 X","3 X","3 Y","3 Y","3 X","3 Y"]]; 

foreach (array_count_values($array[$i]) as $key => $value) { 
       if(strrpos($key, "A")===0 && is_numeric(substr($key,2))) 
       {$keycount1++;} 
       else if(strrpos($key, "A")===0 && !is_numeric(substr($key,2))){ 
       array_push($lettersarray, substr($key, 2)); 
       } 
       $probabilty=round(($value/count($array[$i])),2); 
       echo "$key - <strong>$value</strong> <br/>Probability: $probabilty<br/>"; 
       $names=str_replace(' ', '', $key); 
       $newarray[$key]=$probabilty; 

     }

它正常工作與所有陣列，除了啓動「A X」的一個。我得到如下結果：

A 1 - 6 
Probability: 0.4 
A 2 - 5 
Probability: 0.33 
A 3 - 4 
Probability: 0.27 

A a - 8 
Probability: 0.53 
A c - 7 
Probability: 0.47 

**A X - 5 
Probability: 0.33 
A Y - 3 
Probability: 0.2 
A Z - 5 
Probability: 0.33 
A Z - 1 
Probability: 0.07 
A X - 1 
Probability: 0.07** 

1 a - 7 
Probability: 0.47 
1 b - 5 
Probability: 0.33 
1 c - 3 
Probability: 0.2 

2 a - 10 
Probability: 0.67 
2 b - 5 
Probability: 0.33 

3 b - 7 
Probability: 0.47 
3 c - 6 
Probability: 0.4 
3 a - 2 
Probability: 0.13 

a X - 5 
Probability: 0.33 
a Z - 6 
Probability: 0.4 
a Y - 4 
Probability: 0.27 

b Z - 7 
Probability: 0.47 
b X - 4 
Probability: 0.27 
b Y - 4 
Probability: 0.27 

c Y - 7 
Probability: 0.47 
c Z - 4 
Probability: 0.27 
c X - 4 
Probability: 0.27 

1 Z - 5 
Probability: 0.33 
1 X - 4 
Probability: 0.27 
1 Y - 6 
Probability: 0.4 

2 X - 7 
Probability: 0.47 
2 Y - 6 
Probability: 0.4 
2 Z - 2 
Probability: 0.13 

3 X - 7 
Probability: 0.47 
3 Y - 7 
Probability: 0.47 
3 Z - 1 
Probability: 0.07

爲什麼我得到相同的值兩次？

來源

2014-10-29 yamahamm

我不明白你想要什麼。你能澄清嗎？ – Ali 2014-10-29 12:02:02

我會盡力的。我有一個數組，我需要獲取所有唯一值，以及它們中有多少個，然後計算每個唯一值的概率。順便說一下，一些代碼可以做一些其他的事情 – yamahamm 2014-10-29 12:04:16

代碼適用於我，請參閱https://eval.in/211439 – Paul 2014-10-29 12:09:45

這將返回所有值的計數。

$res = array_icount_values ($array); 
echo '<pre>';print_r($res); 

function array_icount_values($arr, $lower = true) { 
    $arr2 = array(); 
    if (!is_array($arr['0'])) { 
     $arr = array($arr); 
    } 
    foreach ($arr as $k => $v) { 
     foreach ($v as $v2) { 
      if ($lower == true) { 
       $v2 = strtoupper($v2); 
      } 
      if (!isset($arr2[$v2])) { 
       $arr2[$v2] = 1; 
      } else { 
       $arr2[$v2]++; 
      } 
     } 
    } 
    return $arr2; 
}

來源

2014-10-29 12:41:49

仍然得到同樣的結果 – yamahamm 2014-10-29 12:51:43

與array_count_values獲取兩個相同的值

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