2013-04-29 55 views
0

我通常會將顯示區塊放到鏈接中,以使按鈕的所有div都處於活動狀態,而不僅僅是文本。但在這種情況下,我需要在ulli中使用display:inline-block,我認爲這會禁用其他顯示塊?如何使所有的li活躍,不僅在裏面的文字?li中的活動區域

這裏是例子:http://jsfiddle.net/mPGDe/

HTML:

<ul class="menu"> 
    <li><a href="#">first</a></li> 
    <li><a href="#">second</a></li> 
    <li><a href="#l">third</a></li> 
</ul> 

CSS:

ul { 
    margin:40px auto; 
    list-style-type:none; 
    padding:0; 
    text-align: center; 
} 

ul li { 
    position: relative; 
    padding: 7px 17px; 
    margin-right: 10px; 
    background-color: #f2f2f2; 
    display: inline-block; /* does it disable display block? */ 
} 

ul li a { 
    display:block;/* usually to make active all the zone, but here it does not work */ 
} 

回答

1

把墊襯上a而不是li

ul li { 
    position: relative; 
    margin-right: 10px; 
    background-color: #f2f2f2; 
    display: inline-block; /* does it disable display block? */ 
} 

ul li a { 
    padding: 7px 17px; 
    display:block;/* usually to make active all the zone, but here it does not work */ 
} 

演示在http://jsfiddle.net/gaby/mPGDe/1/

+0

是的!而已。所以模擬和清晰。謝謝! – Nrc 2013-04-29 13:48:12