awk打印每第n個匹配行並且所有行不是數學

我知道如何打印每第n行和第n個匹配行，但不知道如何打印每第n個匹配行並且所有行都不是數學。awk打印每第n個匹配行並且所有行不是數學

輸入例：

Something else 1 
Downloading: file1 1% 
Downloading: file1 10% 
Something else 2 
Downloading: file1 30% 
Something else 3 
Downloading: file1 40% 
Downloading: file2 50% 
Downloading: file1 60% 
Downloading: file1 100% 
Downloading: file2 100% 
Something else 4

如果圖案是 '^下載：' 和打印每一第二匹配線，輸出應該是這樣的：

Something else 1 
Downloading: file1 10% 
Something else 2 
Something else 3 
Downloading: file1 40% 
Downloading: file1 60% 
Downloading: file2 100% 
Something else 4

來源

2017-04-11 user2914846

顯示輸入片段nd預期輸出 – RomanPerekhrest

$ awk '!(/Downloading/ && ++c%2)' file 
Something else 1 
Downloading: file1 10% 
Something else 2 
Something else 3 
Downloading: file1 40% 
Downloading: file1 60% 
Downloading: file2 100% 
Something else 4

來源

2017-04-11 18:11:24

好東西！對於標題：「打印**每秒**線，匹配'/下載/'」 – RomanPerekhrest

@EdMorton它的作品。謝謝！ – user2914846

用於Perl球迷：

perl -nlE 'say unless /Downloading/ && ++$n%2'

來源

2017-04-11 18:28:56 jm666

awk打印每第n個匹配行並且所有行不是數學

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