SharpZipLib - 零個字節

所以我複製了他們的樣品下面的代碼片段：

// Compresses the supplied memory stream, naming it as zipEntryName, into a zip, 
// which is returned as a memory stream or a byte array. 
// 
public MemoryStream CreateToMemoryStream(MemoryStream memStreamIn, string zipEntryName) 
{ 
    MemoryStream outputMemStream = new MemoryStream(); 
    ZipOutputStream zipStream = new ZipOutputStream(outputMemStream); 

    zipStream.SetLevel(3); //0-9, 9 being the highest level of compression 

    ZipEntry newEntry = new ZipEntry(zipEntryName); 
    newEntry.DateTime = DateTime.Now; 

    zipStream.PutNextEntry(newEntry); 

    StreamUtils.Copy(memStreamIn, zipStream, new byte[4096]); 
    zipStream.CloseEntry(); 

    zipStream.IsStreamOwner = false; // False stops the Close also Closing the underlying stream. 
    zipStream.Close();   // Must finish the ZipOutputStream before using outputMemStream. 

    outputMemStream.Position = 0; 
    return outputMemStream; 

    // Alternative outputs: 
    // ToArray is the cleaner and easiest to use correctly with the penalty of duplicating allocated memory. 
    byte[] byteArrayOut = outputMemStream.ToArray(); 

    // GetBuffer returns a raw buffer raw and so you need to account for the true length yourself. 
    byte[] byteArrayOut = outputMemStream.GetBuffer(); 
    long len = outputMemStream.Length; 
}

我複製粘貼該函數並把它稱爲是這樣的：

using (MemoryStream ms = new MemoryStream()) 
using (FileStream file = new FileStream(@"c:\file.jpg", FileMode.Open, FileAccess.Read)) 
{ 
    byte[] bytes = new byte[file.Length]; 
    file.Read(bytes, 0, (int)file.Length); 
    ms.Write(bytes, 0, (int)file.Length); 
    var result = SharpZip.CreateToMemoryStream(ms, "file.jpg"); 
    result.WriteTo(new FileStream(@"c:\myzip.zip", FileMode.Create, System.IO.FileAccess.Write)); 
}

myzip.zip成功創建，但file.jpg裏面有零字節。

任何想法？

非常感謝

來源

2014-09-03 Christopher Bailey

你是否已經通過代碼進行了寫作/創建新FileStream的結果是什麼？ – MethodMan 2014-09-03 15:23:01

是的，它是一個有效的內存流。 ** myzip.zip **被創建，** file.jpg **也被創建，但圖像的零字節。 – 2014-09-03 15:25:24

不關閉zipstream關閉底層內存流？這將解釋爲什麼你沒有數據。 – Sign 2014-09-03 15:27:28

有必要寫輸入文件數據後，「倒帶」輸入MemoryStream：

using (MemoryStream ms = new MemoryStream()) 
using (FileStream file = File.OpenRead(@"input file path")) 
{ 
    byte[] bytes = new byte[file.Length]; 
    file.Read(bytes, 0, (int)file.Length); 
    ms.Write(bytes, 0, (int)file.Length); 
    ms.Position = 0; // "Rewind" the stream to the beginning. 
    var result = SharpZip.CreateToMemoryStream(ms, "file.jpg"); 
    using (var outputStream = File.Create(@"output file path")) 
    { 
     result.WriteTo(outputStream); 
    } 
}

替代（略簡體）版本的執行情況：

var bytes = File.ReadAllBytes(@"input file path"); 
using (MemoryStream ms = new MemoryStream(bytes)) 
{ 
    var result = SharpZip.CreateToMemoryStream(ms, "file.jpg"); 
    using (var outputStream = File.Create(@"output file path")) 
    { 
     result.WriteTo(outputStream); 
    } 
}

來源

2014-09-21 07:51:38

SharpZipLib - 零個字節

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