-2
下面這段代碼從數據庫中讀取數據,我想要做的是,當您單擊下面的表單上的提交時,它會將相同的數據寫入另一個數據庫,並且當被拒絕時,它也會將其提交給另一個不同的數據庫。你能幫我嗎?因爲我無法得到如何去做。將數據寫入數據庫
<?php
} else if ($usertype == 1) {
$server = "localhost";
$user = "";
$pass = "r=Sc!~";
$db = "";
$user1 = $_SESSION['username'];
$mysqli = new Mysqli($server, $user, $pass, $db) or mysqli_error($mysqli);
$overrides = $mysqli->query("SELECT * FROM Overrides WHERE professor = '$user1'");
$num_rows = mysqli_num_rows($overrides);
?>
<?php
echo " Overrides today: " . $num_rows;
?>
<form method="post" action="dbheads.php" name="HeadWritingForm" id="HeadWritingForm" autocomplete="off">
<fieldset>
<?php
while($row = mysqli_fetch_array($overrides)) {
echo "First Name: " . $row['name'] . "<br />";
echo "<br />Mid. Name: " . $row['mname'] . "<br />";
echo "<br />Fam. Name: " . $row['fname'] . "<br />";
echo "<br />Student ID: " . $row['sid'] . "<br />";
echo "<br />Scolarship: " . $row['sc'] . "<br />";
echo "<br />Phone No: " . $row['phone'] . "<br />";
echo "<br />Email: " . $row['email'] . "<br />";
echo "<br />Class: " . $row['class'] . "<br />";
echo "<br />Section: " . $row['section'] . "<br />";
echo "<br />Semester: " . $row['semester'] . "<br />";
}
?>
<br />
<div>
<label for="comments" accesskey="c">Notes & Comments:</label><br />
<textarea name="comments" cols="35" rows="10">
</textarea><br>
</div>
<br>
<input type="submit" class="submit" id="submit" value="Accept" /> <input type="submit" value="Deny"><br>
</fieldset>
</form>
,你可以簡單地使用插入查詢和它的作品! wat在這方面很難嗎? –
@HardyMathew請指導我嗎? – Sam
簡單它只是檢查哪個按鈕按下'if(提交){在DB1中插入數據}'else'{在Db2中插入數據}'if'條件' –