如何將兩個用於INSERT的PDO語句組合到數據庫中？

我正在尋找使用一個pdo語句的輸出與另一個語句的數組數據。目前，這兩組語句都單獨工作，但我不知道如何將輸出合併到數據庫中的一個表中。如何將兩個用於INSERT的PDO語句組合到數據庫中？

我試圖更新的數據庫表有3列，recipe_id，item_number和quantity。

我需要的是$recipeID作爲主recipe_id和我的數組的輸出來填充其他兩列。希望我正在感，有人可以幫助，我使用的代碼與意見如下：

<?php 
     //MySQL Database Connect 
     require 'config.php'; 

     //Takes form input for recipe title for insert to the recipe table 
     $name = $_POST["recipeName"]; 

     //Stored procedure inputs the recipe name to the recipe table and outputs a recipe_id which is to be passed into recipe item table below 
     $stmt = $dbh->prepare("CALL sp_add_recipe(:name, @output)"); 
     $stmt->bindParam(':name', $name, PDO::PARAM_STR); 

     //Execute Statment 
     $stmt->execute(); 

     //$recipeID variable stores recipe_id outputted from the stored procedure above 
     $recipeID = $dbh->query("SELECT @output")->fetchColumn(); 

     //Insert places the values from $recipeID, item_number & quantity into the recipe_item table 
     $stmt = $dbh->prepare('INSERT INTO recipe_item (recipe_id, item_number, quantity) VALUES (:recipeID,?,?)'); 
     $stmt ->bindParam(':recipeID',$recipeID, PDO::PARAM_STR); 

     //Ingredients variable combines array values from HTML form 
     $ingredients = array_combine($_POST['recipe']['ingredient'], $_POST['recipe']['quantity']); 

     //Each value from the form is inserted to the recipe_item table as defined above 
     foreach($ingredients as $name => $quantity) 
     { 
      $stmt->execute(); //I would like to insert $recipeID to my database with each line of the array below. 
      $stmt->execute(array($name, $quantity)); 
     } 
    ?>

來源

2012-03-11 php_d

沒有必要在這種情況下更多的使用'mysql_escape_string'（實際上，這是錯誤的，可能會打破字符串）。 PDO在準備好的聲明中執行轉義工作 – 2012-03-11 23:49:38

@Pekka感謝您的更新，我將更新我的代碼，仍然掌握PDO。如果你對如何獲得輸出結果有任何想法，我會非常感激。 – 2012-03-11 23:54:03

當前代碼有什麼問題？ – galymzhan 2012-03-12 05:11:05

$stmt = $dbh->prepare('INSERT INTO recipe_item (recipe_id, item_number, quantity) VALUES (:recipeID,:number,:quantity)'); 

//remove the bindParam() call for recipeId 

$ingredients = array_combine($_POST['recipe']['ingredient'], $_POST['recipe']['quantity']); 

foreach ($ingredients as $name => $quantity) { 
    $bound = array(
     'recipeID' => $recipeID, 
     'number' => $name, // ?? This is what your codes does at the moment, but looks weird 
     'quantity' => $quantity 
    ); 
    $stmt->execute($bound); 
}

來源

2012-03-12 12:29:51

非常感謝，完成了這個把戲。 – 2012-03-12 12:57:01

如何將兩個用於INSERT的PDO語句組合到數據庫中？

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