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我的fsyacc代碼給出了一個編譯器錯誤，說沒有找到變量，但我不知道爲什麼。我希望有人能指出這個問題。爲什麼這個fsyacc輸入產生F＃不能編譯？
%{
open Ast
%}
// The start token becomes a parser function in the compiled code:
%start start
// These are the terminal tokens of the grammar along with the types of
// the data carried by each token:
%token NAME
%token ARROW TICK VOID
%token LPAREN RPAREN
%token EOF
// This is the type of the data produced by a successful reduction of the 'start'
// symbol:
%type <Query> start
%%
// These are the rules of the grammar along with the F# code of the
// actions executed as rules are reduced. In this case the actions
// produce data using F# data construction terms.
start: Query { Terms($1) }
Query:
| Term EOF { $1 }
Term:
| VOID { Void }
| NAME { Conc($1) }
| TICK NAME { Abst($2) }
| LPAREN Term RPAREN { Lmda($2) }
| Term ARROW Term { TermList($1, $3) }
該行| NAME {濃度（$ 1）}和下面的線均可以得到這樣的錯誤：
error FS0039: The value or constructor '_1' is not defined
我理解的語法問題，但什麼是錯的YACC輸入？
如果有幫助，這裏是AST的定義：
namespace Ast
open System
type Query =
| Terms of Term
and Term =
| Void
| Conc of String
| Abst of String
| Lmda of Term
| TermList of Term * Term
而且fslex輸入：
{
module Lexer
open System
open Parser
open Microsoft.FSharp.Text.Lexing
let lexeme lexbuf =
LexBuffer<char>.LexemeString lexbuf
}
// These are some regular expression definitions
let name = ['a'-'z' 'A'-'Z' '0'-'9']
let whitespace = [' ' '\t' ]
let newline = ('\n' | '\r' '\n')
rule tokenize = parse
| whitespace { tokenize lexbuf }
| newline { tokenize lexbuf }
// Operators
| "->" { ARROW }
| "'" { TICK }
| "void" { VOID }
// Misc
| "(" { LPAREN }
| ")" { RPAREN }
// Numberic constants
| name+ { NAME }
// EOF
| eof { EOF }