簡單的矩形終端動畫在Python 3.x

我有一個任務，我必須寫一個函數，它將打印一個矩形（用戶可以改變它的高度和寬度）框架內的「x」（我盡我所能來形容它，但我希望圖像會有所幫助）。簡單的矩形終端動畫在Python 3.x

在我的代碼中，我將frame表示爲行列表（用「o」s填充）。我已經有了一個函數來查找矩形的中心，並用「x」替換中間的「o」 - 這是我的第一幀。

本來我想讓所有剩餘的框架都嵌套循環，但由於有兩條水平線「x」es，所以它相當快地混淆了。

我很確定我需要一個新的「座標系」來遍歷幀。有人能請我指出正確的方向嗎？

def squareAnimation(): 

    while True: 

     frameHeight = int(input("Please enter frame's height: \nRemember: Odd numbers only!\n")) 
     frameWidth = int(input("Please enter frame's width:\nRemember: Odd numbers only!\n")) 


     if (frameHeight % 2 != 0 and frameWidth % 2 != 0): 
      break 
    numberOfFrames = min(int(frameWidth/2), int(frameHeight/2)) 

    lineTemplate = "o " * frameWidth 
    #frame filled with "o" only 
    blankFrame = [lineTemplate] * frameHeight 

    #frame with x in center 
    frameTemplate = blankFrame 
    findListCenter(frameTemplate, frameHeight, frameWidth) 
    printListWithoutBrackets(frameTemplate) 

def findListCenter(frame, height, width): 
    frame[int(height/2)] = "o " * (int(width/2)) + "x " + "o " * (int(width/2)) 

def printListWithoutBrackets(frame): 
    for object in range(0, len(frame)): 
     tempLine = frame[object] 
     print("".join(tempLine)) 

squareAnimation()

來源

2017-10-28 Bartosz Kunat

所以最後我想出了自己的解決方案。它可能不是最漂亮的，但它的工作原理。

import copy 
import time 

def squareAnimation(): 

    while True: 

     height = int(input("Please enter frame's height: \nRemember: Odd numbers only!\n")) 
     width = int(input("Please enter frame's width:\nRemember: Odd numbers only!\n")) 

     if (height % 2 != 0 and width % 2 != 0): 
      break 
    numberOfFrames = min(int(width/2), int(height/2)) 
    middleRow = int(height/2) 
    middleColumn = int(width/2) 

    numberOfHorizontalXes = 3 
    lineTemplate = "o " * width 
    blankFrame = [lineTemplate] * height 
    currentFrameIndex = 1 

    completeListOfFrames = ([blankFrame] * (numberOfFrames + 1)) #an array filled with blankGrames 

    firstFrame = copy.deepcopy(blankFrame) 
    firstFrame [int(height/2)] = "o " * (int(width/2)) + "x " + "o " * (int(width/2)) 

    completeListOfFrames[0] = firstFrame 

    for frame in completeListOfFrames: 
     if frame == firstFrame: 
      continue 

     numberOfO = int((width - numberOfHorizontalXes)/2) 
     loopFrameCopy = copy.deepcopy(frame) 

     loopFrameCopy[middleRow + currentFrameIndex] = "o " * numberOfO + "x " * numberOfHorizontalXes + "o " * numberOfO 
     loopFrameCopy[middleRow - currentFrameIndex] = "o " * numberOfO + "x " * numberOfHorizontalXes + "o " * numberOfO 
     loopFrameCopy[middleRow] = "o " * numberOfO + "x " + "o " * (width - (2 * numberOfO + 2)) + "x " + "o " * numberOfO 

     for wallIndex in range(1, currentFrameIndex): 
      loopFrameCopy[middleRow + wallIndex] = "o " * numberOfO + "x " + "o " * (width - (2 * numberOfO + 2)) + "x " + "o " * numberOfO 
      loopFrameCopy[middleRow - wallIndex] = "o " * numberOfO + "x " + "o " * (width - (2 * numberOfO + 2)) + "x " + "o " * numberOfO 

     completeListOfFrames[currentFrameIndex] = loopFrameCopy 

     numberOfO += 3 
     numberOfHorizontalXes += 2 
     currentFrameIndex += 1 

    revCompleteListOfFrames = copy.deepcopy(completeListOfFrames[::-1]) 
    revCompleteListOfFrames.pop(0) 
    finalList = completeListOfFrames + revCompleteListOfFrames 
    printListWithoutBrackets(finalList) 

def printListWithoutBrackets(frameOfFrames): 

    for frame in frameOfFrames: 
     for line in frame: 

      print("".join(line)) 
     time.sleep(0.3) 
     print("\n") 

squareAnimation()

來源

2017-10-30 15:42:08

簡單的矩形終端動畫在Python 3.x

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