如何在Mac中使用Python獲取活動窗口標題？

Question

我正在嘗試編寫在Mac OS中使用python打印活動窗口標題的Python腳本。

這裏是我的代碼：

from AppKit import NSWorkspace 
active_app_name = NSWorkspace.sharedWorkspace().frontmostApplication().localizedName() 
print active_app_name 

這段代碼只是打印像谷歌Chrome或Firefox，而不是所有權的應用程序的名稱。如何獲得窗口的標題？

Answer 1

以下是我使用Quartz API使用Python在Mac OS X上查找活動應用程序名稱和窗口標題的內容。

首先，我們需要增加進口的需要：

if sys.platform == "darwin": 
    import applescript 
    from AppKit import NSWorkspace 
    from Quartz import (
     CGWindowListCopyWindowInfo, 
     kCGWindowListOptionOnScreenOnly, 
     kCGNullWindowID 
    ) 

然後我們就可以得到通過下面的代碼激活應用程序名稱和窗口標題：

def getActiveInfo(event_window_num): 
    try: 
     if sys.platform == "darwin": 
      app = NSWorkspace.sharedWorkspace().frontmostApplication() 
      active_app_name = app.localizedName() 

      options = kCGWindowListOptionOnScreenOnly 
      windowList = CGWindowListCopyWindowInfo(options, kCGNullWindowID) 
      windowTitle = 'Unknown' 
      for window in windowList: 
       windowNumber = window['kCGWindowNumber'] 
       ownerName = window['kCGWindowOwnerName'] 
       # geometry = window['kCGWindowBounds'] 
       windowTitle = window.get('kCGWindowName', u'Unknown') 
       if windowTitle and (
           event_window_num == windowNumber 
         or ownerName == active_app_name 
       ): 
        # log.debug(
        #  'ownerName=%s, windowName=%s, x=%s, y=%s, ' 
        #  'width=%s, height=%s' 
        #  % (window['kCGWindowOwnerName'], 
        #  window.get('kCGWindowName', u'Unknown'), 
        #  geometry['X'], 
        #  geometry['Y'], 
        #  geometry['Width'], 
        #  geometry['Height'])) 
        break 

      return _review_active_info(active_app_name, windowTitle) 
     if sys.platform == "win32": 
      (active_app_name, windowTitle) = _getActiveInfo_Win32() 
      return _review_active_info(active_app_name, windowTitle) 
    except: 
     log.error('Unexpected error: %s' % sys.exc_info()[0]) 
     log.error('error line number: %s' % sys.exc_traceback.tb_lineno) 
    return 'Unknown', 'Unknown' 

Answer 2

沒有從NSWorkspace.sharedWorkspace().activeApplication()訪問應用標題。

但你可以找到它的PID當前窗口的標題：

例如：

from AppKit import NSWorkspace 
pid = NSWorkspace.sharedWorkspace().activeApplication()['NSApplicationProcessIdentifier'] 

然後使用下面的代碼（它存儲在kCGWindowOwnerPID）找到合適的窗口，如下代碼所示：

這裏是基於@JakeW's script一個完整的殼例如：

#!/usr/bin/python 
# Prints list of windows in the current workspace. 
import sys 
if sys.platform == "darwin": 
    from AppKit import NSWorkspace 
    from Quartz import (
     CGWindowListCopyWindowInfo, 
     kCGWindowListOptionOnScreenOnly, 
     kCGNullWindowID 
    ) 

if sys.platform == "darwin": 
    curr_app = NSWorkspace.sharedWorkspace().frontmostApplication() 
    curr_pid = NSWorkspace.sharedWorkspace().activeApplication()['NSApplicationProcessIdentifier'] 
    curr_app_name = curr_app.localizedName() 
    options = kCGWindowListOptionOnScreenOnly 
    windowList = CGWindowListCopyWindowInfo(options, kCGNullWindowID) 
    for window in windowList: 
     pid = window['kCGWindowOwnerPID'] 
     windowNumber = window['kCGWindowNumber'] 
     ownerName = window['kCGWindowOwnerName'] 
     geometry = window['kCGWindowBounds'] 
     windowTitle = window.get('kCGWindowName', u'Unknown') 
     if curr_pid == pid: 
      print("%s - %s (PID: %d, WID: %d): %s" % (ownerName, windowTitle.encode('ascii','ignore'), pid, windowNumber, geometry)) 
elif sys.platform == "win32": 
    (active_app_name, windowTitle) = _getActiveInfo_Win32() 

它將列出當前活動窗口的詳細信息，包括其標題。