2013-03-26 70 views
0

我寫了一段代碼來計算病人的等待時間如下;簡單的代碼超過時間

$query = "SELECT PatientID, Forename, Surname, Gender, Illness, Priority, Arrival_time, TIME_FORMAT(ABS(TIMEDIFF(CURTIME(), Arrival_time)),'%H hours') as Waiting_Time FROM Patient"; 

哪個顯示以下數據:如示例所示

PatientID Forename Surname Gender Illness  Priority Waiting Time 
625   Max  Courts M  non-urgent moderate 4 hours 

;等待時間爲4小時; 我需要一段代碼來檢測並提醒timeMORE THAN 4小時;以迴應警報。

我試過的示例代碼;

if $waitingtime == >4 hours 
then echo "patient must be seen!" 

編輯全碼

<?php 

$conn = mysqli_connect("localhost","root","") or die ("No connection"); 
mysqli_select_db($conn, "a&e") or die('Could not select database.'); 

$query = "SELECT PatientID, Forename, Surname, Gender, Illness, Priority, Arrival_time, TIME_FORMAT(ABS(TIMEDIFF(CURTIME(), Arrival_time)),'%H hours') as Waiting_Time FROM Patient"; 
$result = mysqli_query($conn, $query) or die("Invalid query"); 

echo "<table border='1'> 
<tr> 
<th>PatientID</th> 
<th>Forename</th> 
<th>Surname</th> 
<th>Gender</th> 
<th>Illness</th> 
<th>Priority</th> 
<th>Waiting Time</th> 
</tr>"; 

while ($row = $result->fetch_object()){ 

echo "<tr> 
    <td>" . $row->PatientID . "</td> 
    <td>" . $row->Forename . "</td> 
    <td>" . $row->Surname . "</td> 
    <td>" . $row->Gender . "</td> 
    <td>" . $row->Illness . "</td> 
    <td>" . $row->Priority . "</td> 
    <td>" . $row->Waiting_Time . "</td> 
    </tr>"; 

} 

echo "</table>"; 
mysqli_close($conn); 
?> 
+0

上一個相同的問題仍然是打開的。如果您沒有得到很好的答案,請考慮更新它,而不是創建相同的答案。 – Tchoupi 2013-03-26 17:34:19

+0

因爲我需要幫助,而且我多次編輯了這個問題 – 2013-03-26 18:02:43

回答

0

我使用mysql_ *爲示範開始的目的。你應該使用mysqli_ *或PDO。

$query = "SELECT PatientID, Forename, Surname, Gender, Illness, Priority, Arrival_time, TIME_FORMAT(ABS(TIMEDIFF(CURTIME(), Arrival_time)),'%H') as Waiting_Time FROM Patient"; 

$result = mysql_query($query); 
$row = mysql_fetch_assoc($result); 
if ($row['Waiting_Time '] > 4) 
{ 
    echo "patient must be seen!" 
} 
+0

問題已被編輯以顯示完整的代碼。我將如何編輯代碼以使您的解決方案適用? – 2013-03-26 18:11:55