1
我有一個ubuntu服務器,我可以使用ssh連接運行python解釋器。 我想將解釋器鏈接到我的IDE之一。spyder和遠程ssh python intepreter
spyder是否支持遠程ssh intepreter?如果不是什麼是可能的免費選擇?
編輯: 隨着spyder的新版本,它似乎有可能連接到遠程外殼。 但是當我嘗試連接我收到此錯誤
>>> Traceback (most recent call last):
File "/home/donbeo/Applications/spyder-ide-3.4dev/spyderlib/plugins/ipythonconsole.py", line 973, in create_client_for_kernel
self._create_client_for_kernel(cf, hostname, kf, pw)
File "/home/donbeo/Applications/spyder-ide-3.4dev/spyderlib/plugins/ipythonconsole.py", line 1007, in _create_client_for_kernel
if not self.kernel_and_frontend_match(cf):
File "/home/donbeo/Applications/spyder-ide-3.4dev/spyderlib/plugins/ipythonconsole.py", line 898, in kernel_and_frontend_match
profile='default')
File "/usr/lib/python2.7/dist-packages/IPython/kernel/connect.py", line 273, in get_connection_info
info = json.loads(info)
File "/usr/lib/python2.7/json/__init__.py", line 338, in loads
return _default_decoder.decode(s)
File "/usr/lib/python2.7/json/decoder.py", line 366, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "/usr/lib/python2.7/json/decoder.py", line 384, in raw_decode
raise ValueError("No JSON object could be decoded")
ValueError: No JSON object could be decoded
Traceback (most recent call last):
File "/home/donbeo/Applications/spyder-ide-3.4dev/spyderlib/plugins/ipythonconsole.py", line 973, in create_client_for_kernel
self._create_client_for_kernel(cf, hostname, kf, pw)
File "/home/donbeo/Applications/spyder-ide-3.4dev/spyderlib/plugins/ipythonconsole.py", line 1007, in _create_client_for_kernel
if not self.kernel_and_frontend_match(cf):
File "/home/donbeo/Applications/spyder-ide-3.4dev/spyderlib/plugins/ipythonconsole.py", line 898, in kernel_and_frontend_match
profile='default')
File "/usr/lib/python2.7/dist-packages/IPython/kernel/connect.py", line 273, in get_connection_info
info = json.loads(info)
File "/usr/lib/python2.7/json/__init__.py", line 338, in loads
return _default_decoder.decode(s)
File "/usr/lib/python2.7/json/decoder.py", line 366, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "/usr/lib/python2.7/json/decoder.py", line 384, in raw_decode
raise ValueError("No JSON object could be decoded")
ValueError: No JSON object could be decoded
您認爲這個功能將在幾周內被包含在pip版本中嗎? – Donbeo 2014-08-29 09:52:49
@Donbeo沒有確切的日期,但從源代碼運行spyder非常簡單:安裝mercurial,克隆存儲庫並運行python bootstrap.py。 – Quant 2014-08-29 13:22:00
如果您認爲這是對您問題的正確答案,請驗證答案。 – Quant 2014-08-29 15:49:03