std ::在類內部綁定一個靜態成員函數

Question

我想存儲一個函數以後再調用，這裏是一個片段。

這工作得很好：

void RandomClass::aFunc(int param1, int param2, double param3, bool isQueued /*= false */) 
{ 
    /* If some condition happened, store this func for later */ 
    auto storeFunc = std::bind (&RandomClass::aFunc, this, param1, param2, param3, true); 

    CommandList.push(storeFunc); 

    /* Do random stuff */ 
} 

但是，如果RandomClass是靜態的，所以我相信我應該這樣做：

void RandomClass::aFunc(int param1, int param2, double param3, bool isQueued /*= false */) 
{ 
    /* If some condition happened, store this func for later */ 
    auto storeFunc = std::bind (&RandomClass::aFunc, param1, param2, param3, true); 

    CommandList.push(storeFunc); 

    /* Do random stuff */ 
} 

但是，這並不工作，我得到的編譯錯誤

錯誤C2668：'std :: tr1 :: bind'：對超載函數的模糊調用

任何幫助讚賞。

Answer 1

類型的指針的靜態成員函數的看起來像一個指針指向一個非成員fuinction：

auto storeFunc = std::bind ((void(*)(WORD, WORD, double, bool)) 
           &CSoundRouteHandlerApp::MakeRoute, 
           sourcePort, destPort, volume, true); 

下面是一個簡化的例子：

struct Foo 
{ 
    void foo_nonstatic(int, int) {} 
    static int foo_static(int, int, int) { return 42;} 
}; 

#include <functional> 
int main() 
{ 
    auto f_nonstatic = std::bind((void(Foo::*)(int, int))&Foo::foo_nonstatic, Foo(), 1, 2); 
    auto f_static = std::bind((int(*)(int, int, int))&Foo::foo_static, 1, 2, 3); 

}