Opencv .at方法不按預期工作？

Question

試圖執行一些簡單的轉換，讓我的相機更易於管理的座標姿態和我一直運行到一個問題：

vector< Mat> newpoints; 

    Mat oldpoint = Mat::zeros(4,1, CV_32F); 

    oldpoint.at<float>(3,0) = 1.0; 

    Mat translation = Mat::zeros(4, 4, CV_32F); 
    Mat rotation = Mat::zeros(4, 4, CV_32F); 
    Mat tmp_rot = Mat::zeros(3,3,CV_32F); 
    Mat trans; 
    Mat rota; 

cout << "rearranging coords" << endl; 

for(int i = 0; i < tvecs.size(); i++){ 
    trans = tvecs[i]; 
    rota = rvecs[i]; 

    translation.at<float>(0,0) = 1.0; 
    translation.at<float>(1,1) = 1.0; 
    translation.at<float>(2,2) = 1.0; 
    translation.at<float>(3,3) = 1.0; 

    translation.at<float>(0,3) = trans.at<float>(0); 
    translation.at<float>(1,3) = trans.at<float>(1); 
    translation.at<float>(2,3) = trans.at<float>(2); 

    Rodrigues(rota, tmp_rot); 

    rotation.at<float>(0,0) = tmp_rot.at<float>(0,0); 
    rotation.at<float>(0,1) = tmp_rot.at<float>(0,1); 
    rotation.at<float>(0,2) = tmp_rot.at<float>(0,2); 
    rotation.at<float>(1,0) = tmp_rot.at<float>(1,0); 
    rotation.at<float>(1,1) = tmp_rot.at<float>(1,1); 
    rotation.at<float>(1,2) = tmp_rot.at<float>(1,2); 
    rotation.at<float>(2,0) = tmp_rot.at<float>(2,0); 
    rotation.at<float>(2,1) = tmp_rot.at<float>(2,1); 
    rotation.at<float>(2,2) = tmp_rot.at<float>(2,2); 
    rotation.at<float>(3,3) = 1.0; 
} 

內的賦值，當我使用右邊的.AT這邊沒有意義。它們與原始矩陣中的值完全不同。

Answer 1

就像Micha指出的那樣，類型不匹配。

通過修正：

tvecs[i].convertTo(trans, CV_32F); 
    rvecs[i].convertTo(rota, CV_32F); 
    //trans = tvecs[i]; 
    //rota = rvecs[i];