使用9i中

Question

MERGE我想要做這樣的事情在9i中

MERGE INTO SAT_DEMANDS D 
     USING (SELECT DISTINCT d1.PRODUCT_ID AS product_id, CA.CUST_ID as allocated_cust 
     FROM CDP_MPS_ALLOCATION CA, sat_demands d1 
     WHERE substr(d1.product_id,1,instr(d1.product_id,'_VIRTUAL',1)-1) = ca.prod_id(+)) MC 
     ON (D.PRODUCT_ID = MC.product_id AND D.CUSTOMER_ID = MC.allocated_cust) 
     WHEN matched then 
     Update set D.alloc_cust_id_s = CASE WHEN mc.allocated_cust IS NULL THEN 'FREE' 
             ELSE mc.allocated_cust||':'||'FREE' 
             END; 

請幫幫忙！ Oracle 9i不允許我這樣做，因爲它沒有匹配時沒有。我如何在9i中取得相同的結果？

Answer 1

使用ROWID方法：

FOR r in (SELECT D.rowid, MC.allocated_cust FROM 
      (SELECT DISTINCT d1.PRODUCT_ID AS product_id, CA.CUST_ID as allocated_cust 
       FROM CDP_MPS_ALLOCATION CA, sat_demands d1 
      WHERE substr(d1.product_id,1,instr(d1.product_id,'_VIRTUAL',1)-1) = ca.prod_id(+) 
      ) MC 
      join SAT_DEMANDS D 
      ON (D.PRODUCT_ID = MC.product_id AND D.CUSTOMER_ID = MC.allocated_cust) 
     ) 
LOOP 

     Update SAT_DEMANDS D 
     set D.alloc_cust_id_s = CASE WHEN r.allocated_cust IS NULL THEN 'FREE' 
            ELSE r.allocated_cust||':'||'FREE' 
             END 
     where rowid=r.rowid; 
END LOOP; 

Answer 2

的Oracle 9i中確實有WHEN NOT MATCHED條款。但不能使用更新。

你的情況，你不需要合併，UPDATE應該做你想要什麼：

UPDATE sat_demands d 
    SET alloc_cust_id_s = nvl((SELECT mc.allocated_cust || ':FREE' 
           FROM mc 
           WHERE d.product_id = mc.product_id 
           AND d.customer_id = mc.allocated_cust), 
          'FREE')