For循環條件問題

Question

我有麻煩搞清楚我的JavaScript學習課程的條件。

我沒有得到正常的錯誤，因爲我在使用過程中這樣做，但我在使用過程中接收到錯誤是這樣的......

Oops, try again. Careful: your second 'for' loop should stop when it reaches its current point in the string + myName.length.

這些都說明：

First, you'll want to set your second loop's iterator to start at the first one, so it picks up where that one left off. If your first loop starts with 

for(var i = 0; // rest of loop setup 
your second should be something like 

for(var j = i; // rest of loop setup 
Second, think hard about when your loop should stop. Check the Hint if you get stuck! 

Finally, in the body of your loop, have your program use the .push() method of hits. Just like strings and arrays have a .length method, arrays have a .push() method that adds the thing between parentheses to the end of the array. For example, 

newArray = []; 
newArray.push('hello'); 
newArray[0]; // equals 'hello' 

這是我的代碼

var text = "Hello, my name is Becky. What is your name?\ 
I repeat, my name is Becky. Can't you figure out that my\ 
name is Becky. Becky!!!!"; 
var myName = "Becky"; 
var hits = []; 
for (i = 0; i < text.length; i++) { 
    if (text[i] === 'B') { 
     for (var j = i; i < myName.length; i++) { 
      hits.push(); 
     } 
    } 
} 

我知道問題在於這一行：

for (var j = i; i < myName.length; i++) {

我只是無法弄清楚到底我需要構造它。

UPDATE：問題

最終的答案：

/*jshint multistr:true */ 
var text = "Hello, my name is Becky. What is your name?\ 
I repeat, my name is Becky. Can't you figure out that my\ 
name is Becky. Becky!!!!"; 
var myName = "Becky"; 
var hits = []; 
for (i = 0; i < text.length; i++) { 
    if (text[i] === 'B') { 
     for (var j = i; j < (i + myName.length); j++) { 
      hits.push(myName); 
     } 
    } 
} 
if (hits === 0) { 
    console.log("Your name wasn't found!"); 
} else { 
    console.log(hits); 
} 

Answer 1

我會給你提供解決方案，因爲你可以從直接解決方案中學到更多東西，而不是從你的頭上猛擊。

var text = "Hello, my name is Becky. What is your name?\ 
I repeat, my name is Becky. Can't you figure out that my\ 
name is Becky. Becky!!!!"; 
var myName = "Becky"; 
var hits = []; 
for (i = 0; i < text.length; i++) { 
    if (text[i] == 'B') { 
     var equal = true; 
     for (var j = 0; j < myName.length; j++) { 
      if (text[i + j] != myName[j]) { 
       equal = false; 
       break; 
      } 
     } 
     if(equal) hits.push(myName); 
    } 
} 

可能有其他方法可以達到此結果。這是其中之一。

Explaing什麼是 「推」 的作用：

數組是變量列表。你在一個變量中存儲的值是這樣的：

var myNumber = 777; 
var myName = "Nelson"; 

數組聲明如下所示：

var myNumbers = []; 

然後你把東西在它的內部，像這樣：

myNumbers.push(333); 
myNumbers.push(555); 
myNumbers.push(777); 

然後如果您嘗試：console.log(myNumbers)，它將打印：[333,555,777]

如果您添加ano療法推：

myNumbers.push(999); 

將增加999導致[333, 555, 777, 999]

入住這demo

得到了它的名單？看看這裏更詳細的解釋：

http://www.hunlock.com/blogs/Mastering_Javascript_Arrays

Answer 2

我不知道你想達到什麼目的，

下面是一些可以幫助

var text = "Hello, my name is Becky. What is your name?\ 
I repeat, my name is Becky. Can't you figure out that my\ 
name is Becky. Becky!!!!"; 
var myName = "Becky"; 
var hits = []; 
for (i = 0; i < text.length; i++) { 
    if (text[i] == 'B') { 
     var res = ''; 
     for (var j = i; j < i+myName.length; j++) { 
      res = res+text[j]; 
     } 
     if(res == myName) 
     { 
      hits.push(myName); 
     } 
    } 
} 
console.log(hits); 

這裏demo